Bourbaki

Exercise 10, § 3

Integration, VIII, p. 63

Bourbaki marks this one as harder than the rest.

For a locally compact space T, one denotes by C∞(T)\mathscr{C}^\infty(T) the Banach space of continuous bounded numerical functions on T. A subset H of M1(T)\mathscr{M}^1(T) is said to be cramped if, for every ε>0\varepsilon > 0, there exists a compact subset K of T such that ∣μ∣(T−K)≤ε|\mu|(T - K) \leq \varepsilon for all μ∈H\mu \in H.

a) Show that if a subset H of M1(G)\mathscr{M}^1(G) is cramped and is bounded for the topology defined by the norm of M1(T)\mathscr{M}^1(T), then it is relatively compact for the topology σ(M1(T),C∞(T))\sigma(\mathscr{M}^1(T), \mathscr{C}^\infty(T)) (observe that H is relatively compact for σ(M1(T),K(T))\sigma(\mathscr{M}^1(T), \mathscr{K}(T))).

b) Assuming in addition that T is paracompact, show that, conversely, if H is a subset of M1(T)\mathscr{M}^1(T) relatively compact for σ(M1(T),C∞(T))\sigma(\mathscr{M}^1(T), \mathscr{C}^\infty(T)), then H is bounded for the norm of M1(T)\mathscr{M}^1(T) and is cramped. (Consider first the case that T=NT = \mathbf{N}, applying Exer. 15 of Ch. V, §5. Then contemplate the case that T is countable at infinity, the union of a sequence (Un)(U_n) of relatively compact open sets such that U‾n⊂Un+1\overline{U}_n \subset U_{n+1}. Arguing by contradiction, show that one can reduce to the case that there would exist for each n a continuous numerical function fnf_n defined on T, with support contained in Un+1−U‾nU_{n+1} - \overline{U}_n, such that ∥fn∥≤1\|f_n\| \leq 1, and a sequence (μn)(\mu_n) of measures belonging to H and for which μn(fn)≥a>0\mu_n(f_n) \geq a > 0 for all n. Consider then the continuous mapping u:L1(N)→C∞(T)u : L^1(\mathbf{N}) \to \mathscr{C}^\infty(T) such that u((ξn))=∑n=0∞ξnfnu((\xi_n)) = \sum_{n=0}^\infty \xi_n f_n and obtain a contradiction to what was proved for T=NT = \mathbf{N}, by considering the transpose of u. Finally, when T is an arbitrary paracompact locally compact space, T is the topological sum of a family (Tα)(T_\alpha) of locally compact spaces that are countable at infinity; for every α\alpha, let mα=sup⁡μ∈H∣μ∣(Tα)m_\alpha = \sup_{\mu \in H} |\mu|(T_\alpha); show, arguing by contradiction and making use of the preceding case, that necessarily mα=0m_\alpha = 0 except for a countable infinity of indices α\alpha.)

c) Show that the conclusion of b) is not valid for the non-paracompact locally compact space defined in Exer. 16 h) of Ch. IV, §4.

Solution

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