Bourbaki

Exercise 3, § 3

Integration, VIII, p. 62

For x=(x1,…,xn)∈Rnx = (x_1, \ldots, x_n) \in \mathbf{R}^n one sets ∣x∣2=x12+⋯+xn2|x|^2 = x_1^2 + \cdots + x_n^2. Let M1\mathscr{M}_1 be the set of measures μ\mu on Rn\mathbf{R}^n for which there exists a real number kk such that the function (1+∣x∣2)k(1 + |x|^2)^k is μ\mu-integrable. Let M2\mathscr{M}_2 be the set of measures ν\nu on Rn\mathbf{R}^n for which the function (1+∣x∣2)k(1 + |x|^2)^k is ν\nu-integrable for every kk. Show that if μ∈M1\mu \in \mathscr{M}_1 and ν∈M2\nu \in \mathscr{M}_2, then μ\mu and ν\nu are convolvable, and μ∗ν∈M1\mu * \nu \in \mathscr{M}_1; if μ∈M2\mu \in \mathscr{M}_2 and ν∈M2\nu \in \mathscr{M}_2, then μ∗ν∈M2\mu * \nu \in \mathscr{M}_2. (One first shows that if u≥0, v≥0u \geq 0,\ v \geq 0, then

(1+u2)(1+v2)≥13(1+(u+v)2); (1 + u^2)(1 + v^2) \geq \frac{1}{3}(1 + (u + v)^2);

from this, one deduces that for any x,yx, y in Rn\mathbf{R}^n,

1+∣x∣2≤3(1+∣y∣2)(1+∣x+y∣2). 1 + |x|^2 \leq 3(1 + |y|^2)(1 + |x + y|^2).

Then let μ∈M1, ν∈M2\mu \in \mathscr{M}_1,\ \nu \in \mathscr{M}_2 with μ≥0, ν≥0\mu \geq 0,\ \nu \geq 0. Let ff be a continuous function ≥0\geq 0 on Rn\mathbf{R}^n. There exists a kk such that μ=(1+∣x∣2)k⋅μ1\mu = (1 + |x|^2)^k \cdot \mu_1 with μ1\mu_1 bounded; let ν1=(1+∣x∣2)k⋅ν\nu_1 = (1 + |x|^2)^k \cdot \nu, which is bounded. Then

∫∗f(x+y) dμ(x) dν(y)≤3k∫∗(1+∣x∣2)kf(x) d(μ1∗ν1)(x). \int^* f(x + y)\ d\mu(x)\ d\nu(y) \leq 3^k \int^* (1 + |x|^2)^k f(x)\ d(\mu_1 * \nu_1)(x).

Whence the convolvability of μ\mu and ν\nu and the fact that μ∗ν∈M1\mu * \nu \in \mathscr{M}_1. Argue in an analogous manner for μ,ν\mu, \nu in M2\mathscr{M}_2.

Solution

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Transcribed from the printed volume. Not translated.