Bourbaki

Exercise 4, § 4

Integration, VIII, p. 65

Bourbaki marks this one as harder than the rest.

Let G be a locally compact group. For every t∈R+∗t \in \mathbf{R}_+^*, let μt\mu_t be a nonzero bounded positive measure on G. Assume that the mapping t↦μtt \mapsto \mu_t is continuous for the topology σ(M1(G),K(G)‾)\sigma(\mathscr{M}^1(G), \overline{\mathscr{K}(G)}), and that μs+t=μs∗μt\mu_{s+t} = \mu_s * \mu_t (s, t in R+∗\mathbf{R}_+^*). a) Show that there exists a number c∈Rc \in \mathbf{R} such that ∥μt∥=exp⁡(ct)\| \mu_t \| = \exp(ct). (Observe that t↦∥μt∥t \mapsto \| \mu_t \| is lower semi-continuous and that ∥μs+t∥=∥μs∥⋅∥μt∥\| \mu_{s+t} \| = \| \mu_s \| \cdot \| \mu_t \|. Make use of Prop. 18.) b) Suppose that c=0c = 0. Show that μt\mu_t converges weakly as t→0t \to 0 to the normalized Haar measure of a compact subgroup of G. (Make use of the weak compactness of the unit ball of M1(G)\mathscr{M}^1(G), and show that for every weak cluster point μ\mu of t↦μtt \mapsto \mu_t with respect to the filter of neighborhoods of 0 in R+∗\mathbf{R}_+^*, one has μt∗μ=μt\mu_t * \mu = \mu_t for every tt, then μ∗μ=μ\mu * \mu = \mu; next, apply Exer. 3.)

Solution

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