Exercise 17, § 4
Lie Groups and Lie Algebras, II, 192
Bourbaki marks this one as harder than the rest.
Suppose that G is nilpotent. Let P be a set of prime numbers and let be the set of normal subgroups of G of finite index whose index is a P-integer (cf. Exercise 14). Let be the topology defined on G by the filter base (General Topology, Chapter III, § 1, no. 2, Example). (a) Let N be a subgroup of G of finite index such that is a P-integer and let N' be the intersection of the conjugates of N. Show that is a P-integer (use the fact that the group G/N' is the product of its Sylow groups); deduce that N is open with respect to . (b) Let H be a subgroup of G of finite index. Show that coincides with the topology induced on H by . (Same method.) (c) Let H be a normal subgroup of G such that G/H is isomorphic to and let x be a representative in G of a generator of G/H. Let and let . Show that and that . If is the subgroup generated by N' and x, show that . Deduce that is induced by . (d) Suppose that G is finite. Show that, if H is a subgroup of G, there exists a sequence of subgroups
(e) With the hypotheses of (d), let denote the complement of in the set of prime numbers. Show that the closure of under coincides with the -saturation of in (Exercise 14); in particular, is Hausdorff if and only if it is -torsion-free.
Solution
No solution has been written yet.