Bourbaki

Exercise 3, § 4

Lie Groups and Lie Algebras, II, 188

Bourbaki marks this one as harder than the rest.

Let (Hα)(H_\alpha) be a real filtration on a group HH and let vHv_H be the corresponding order function. Suppose that GG operates on HH on the left and that, for all g∈Gg \in G, the mapping h↦g(h)h \mapsto g(h) is an automorphism of the filtered group HH.

(a) If α∈R\alpha \in \mathbf{R}, we denote by GαG_\alpha the set of g∈Gg \in G such that

vH(h−1g(h))≥vH(h)+αfor all h∈H. v_H(h^{-1}g(h)) \geq v_H(h) + \alpha \quad \text{for all } h \in H.
Show that (Gα)(G_\alpha) is a real filtration of GG and that Gα=GG_\alpha = G if α≤0\alpha \leq 0. Let vv denote the corresponding order function.

(b) Suppose that the filtration (Hα)(H_\alpha) is central and that G0+=GG_0^+ = G. Show that (Gα)(G_\alpha) is a central filtration of GG. If ξ∈gr⁡α(G)\xi \in \operatorname{gr}_\alpha(G) and η∈gr⁡β(H)\eta \in \operatorname{gr}_\beta(H), let gg (resp. hh) be a representative of ξ\xi (resp. η\eta) in GαG_\alpha (resp. HβH_\beta); show that the image of h−1g(h)h^{-1}g(h) in gr⁡α+β(H)\operatorname{gr}_{\alpha+\beta}(H) is independent of the choice of gg and hh; if it is denoted by Dξ(η)D_\xi(\eta), show that DξD_\xi can be extended to a derivation of the Lie algebra gr⁡(H)\operatorname{gr}(H) of degree α\alpha and that ξ↦Dξ\xi \mapsto D_\xi is a homomorphism of the Lie algebra gr⁡(G)\operatorname{gr}(G) into the Lie algebra of derivations of gr⁡(H)\operatorname{gr}(H). If vH(H)∩Rv_H(H) \cap \mathbf{R} is contained in a discrete subgroup Γ\Gamma of R\mathbf{R}, so is v(G)∩Rv(G) \cap \mathbf{R} and, for all α∈R\alpha \in \mathbf{R}, the mapping ξ↦Dξ\xi \mapsto D_\xi defined above is injective.

Solution

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Transcribed from the printed volume. Not translated.