Bourbaki

Exercise 4, § 5

Lie Groups and Lie Algebras, II, 195

For all n∈Nn \in \mathbf{N}, let (Tn)\binom{T}{n} denote the polynomial

T(T−1)…(T−n+1)/n!. T(T - 1) \ldots (T - n + 1)/n!.

† For more details on this exercise, see K. W. Gruenberg, Lecture Notes in Math., no. 143, Chapter 3, and R. Swan, J. of Algebra, 12 (1969), pp. 585–601.

If f(T)f(T) is a polynomial, let Δf\Delta f denote the polynomial f(T+1)−f(T)f(T + 1) - f(T). Then Δ(T0)=Δ1=0\Delta \binom{T}{0} = \Delta 1 = 0 and Δ(Tn)=(Tn−1)\Delta \binom{T}{n} = \binom{T}{n-1} if n≥1n \geq 1.

(a) Let f∈Q[T]f \in \mathbf{Q}[T]. Show the equivalence of the following properties: (i) ff maps Z\mathbf{Z} into itself. (ii) ff is a linear combination with coefficients in Z\mathbf{Z} of the (Tn)\binom{T}{n}. (iii) f(0)∈Zf(0) \in \mathbf{Z} and Δf\Delta f maps Z\mathbf{Z} into itself. (Argue by induction on deg⁡(f)\deg(f), noting that deg⁡(Δf)=deg⁡(f)−1\deg(\Delta f) = \deg(f) - 1 if deg⁡(f)≠0\deg(f) \neq 0.) A polynomial ff satisfying the above properties is called binomial. The sum, product and composition of two binomial polynomials is a binomial polynomial.

(b) Let pp be a prime number and let ff be a binomial polynomial. Show that ff maps the ring Zp\mathbf{Z}_p of pp-adic integers into itself (use the continuity of ff and the fact that Z\mathbf{Z} is dense in Zp\mathbf{Z}_p).

(c) Let PP be a set of prime numbers, let SPS_P be the set of PP-integers (§ 4, Exercise 14) and let ZP=SP−1Z\mathbf{Z}_P = S_P^{-1}\mathbf{Z}. Show that if ff is a binomial polynomial, ff maps ZP\mathbf{Z}_P into itself (apply (b) to the prime numbers pp not belonging to PP).

Solution

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