Bourbaki

Exercise 5, § 3

Lie Groups and Lie Algebras, III, 374

Let E be the real vector space of Hermitian complex matrices with 2 rows and 2 columns of zero trace. For all s∈SU(2,C)s \in \mathbf{SU}(2, \mathbf{C}), we define an automorphism φ(s)\varphi(s) of E by φ(s)(m)=sms∗\varphi(s)(m) = sms^*. We identify the element

(xy+izy−iz−x) \begin{pmatrix} x & y + iz \\ y - iz & -x \end{pmatrix}
of E with the element (x,y,z)(x, y, z) of R3\mathbf{R}^3. By imitating the method of Exercise 3, show that φ\varphi is a morphism of the real Lie group SU(2,C)\mathbf{SU}(2, \mathbf{C}) onto the real Lie group SO(3,R)\mathbf{SO}(3, \mathbf{R}) with kernel {I,−I}\{I, -I\} and that SO(3,R)\mathbf{SO}(3, \mathbf{R}) is isomorphic to SU(2,C)/{I,−I}\mathbf{SU}(2, \mathbf{C})/\{I, -I\}

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