Exercise 8, § 3
Lie Groups and Lie Algebras, III, 375
Let be a finite-dimensional connected real Lie group and a finite-dimensional connected manifold of class ; let there be given a law of right operation of class of on . For all , let be the corresponding orbital mapping.
(a) For to operate transitively on , it is necessary and sufficient that, for all , the mapping of into be surjective. (To see that the condition is sufficient, observe that then every -orbit in is open.)
(b) Suppose that operates transitively on . We identify with a homogeneous space , where is the stabilizer of a point of . The action of on is called imprimitive if there exists a closed submanifold of of class such that and for which every transform (where ) is either equal to or disjoint from . For this to be so, it is necessary and sufficient that there exist a Lie subgroup of such that and . If this is not so, the action of on is called primitive; for this it suffices that there exist no subalgebra of lying between and and distinct from and .
(c) Under the hypothesis of (b), let be the image of under the law of infinitesimal operation associated with the action of . Let be the algebra of functions of class on and the maximal ideal of consisting of the functions in which are zero at ; we denote by for the set of such that for all ; then and is the image of under the law of infinitesimal operation. If is a chart of centered on and are the vector fields on defined by the chart, the elements of are the with in . Show that (with the convention ). If there exists (for ) such that , there exists such that . The are Lie subalgebras of . For , is an ideal of . Let be the canonical linear representation of on . The Lie algebra of is isomorphic to .
(d) Suppose further that the intersection of the is . Then there exists a greatest index such that and all the of indices are distinct. For ,
Solution
No solution has been written yet.