Bourbaki

Exercise 3, § 4

Lie Groups and Lie Algebras, III, 376

Let G be a Lie group, U an open neighbourhood of 0 in L(G) and ϕ\phi an analytic mapping of U into G such that ϕ(0)=e\phi(0) = e and T0ϕ=IdL(G)T_0 \phi = \mathrm{Id}_{L(G)}. The following conditions are equivalent: (a) ϕ\phi is an exponential mapping; (b) There exists m∈Zm \in \mathbf{Z} distinct from 0, 1, -1 such that ϕ(mx)=ϕ(x)m\phi(mx) = \phi(x)^m in a neighbourhood of 0. (If condition (b) holds, show that ϕ∗\phi^* satisfies condition (iii) of Theorem 4.)

Solution

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