Bourbaki

Exercise 2, § 5

Lie Groups and Lie Algebras, III, 383

Let G be a group of class CrC^r with r≥2r \geq 2. (a) Let t∈T(s)(G)t \in \mathscr{T}^{(s)}(G), t′∈T(s′)(G)t' \in \mathscr{T}^{(s')}(G). If s+s′≤rs + s' \leq r, define t∗t′∈T(s+s′)(G)t * t' \in \mathscr{T}^{(s+s')}(G) as in § 3, no. 1. If t and t′t' are without constant term, t∗t′t * t' is without constant term. The image of t under the mapping x↦x−1x \mapsto x^{-1} of G into G is denoted by t∨t^\vee; then t∨∈T(s)(G)t^\vee \in \mathscr{T}^{(s)}(G). If ff is a function of class CrC^r on G with values in a Hausdorff polynormed space, f∗tf * t denotes the function on G defined by (f∗t)(x)=⟨εx∗t∨,f⟩(f * t)(x) = \langle \varepsilon_x * t^\vee, f \rangle for all x∈Gx \in G; this function is of class Cr−sC^{r-s} if s<∞s < \infty. Show, as in § 3, no. 4, that f∗(t∗t′)=(f∗t)∗t′f * (t * t') = (f * t) * t'. (b) If t∈Te(G)t \in T_e(G), the vector field x↦εx∗tx \mapsto \varepsilon_x * t on G is denoted by LtL_t. Show, as in § 3, no. 6, that, for t,t′t, t' in Te(G)T_e(G), Lt∗t′=Lt∘Lt′L_{t*t'} = L_t \circ L_{t'} and hence that

Lt∗t′−t′∗t=[Lt,Lt′]. L_{t*t'-t'*t} = [L_t, L_{t'}].
Therefore, t∗t′−t′∗tt * t' - t' * t is an element of Te(G)T_e(G) which we denote by [t,t′][t, t']. (c) Using the notation of Exercise 1 (a), if t∈Te(G)t \in T_e(G), then
Lt(x)=(D2P(x,0))(t) L_t(x) = (D_2P(x, 0))(t)
for xx sufficiently close to 0. Deduce that [t,t′]=B(t,t′)−B(t′,t)[t, t'] = B(t, t') - B(t', t). (d) Show that Te(G)T_e(G), with the bracket (t,t′)↦[t,t′](t, t') \mapsto [t, t'], is a normable Lie algebra. (To prove the Jacobi identity, use (c), Exercise 1 (b) and identity (5) of Algebra, Chapter I, § 6, no. 2.) (For a sequel to this exercise, cf. § 8, Exercise 6.)

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