Exercise 16, § 6
Lie Groups and Lie Algebras, III, 386
Bourbaki marks this one as harder than the rest.
(a) Let be a complex Lie algebra. Let be the complex Lie algebra derived from using the automorphism of . Let be the real Lie algebra derived from by restriction of scalars. Let be the complex Lie algebra . For all , we write
Show that (resp. ) is an isomorphism of (resp. ) onto an ideal (resp. ) of and that the ideals are supplementary in . This defines projectors of onto . Show that, for all , , .
(b) Suppose that is finite-dimensional. Let be the simply connected complex Lie group with Lie algebra . Let be the conjugate complex Lie group and the underlying real Lie group. Then and . Let (resp. ) be the simply connected complex Lie group with Lie algebra (resp. ). Then defines an isomorphism of onto , defines an isomorphism of onto and the simply connected complex Lie group with with Lie algebra is identified with . Show that the real integral subgroup of with Lie algebra is closed and simply connected and is identified with . The restriction to of (resp. ) is the isomorphism (resp. ) of (resp. ) onto (resp. ).
(c) Deduce from (b) and Remark 2 of no. 10 that , with the canonical injection of into , is the universal complexification of .
(d) Let be a connected complex Lie group with Lie algebra , the conjugate complex Lie group and the underlying real Lie group, such that is the universal covering space of . Let be the (discrete) kernel of the canonical morphism of onto . Show that is a central subgroup of . The canonical injection of into therefore defines an injection of into . Show that is the universal complexification of . (Note that this ordered pair has the universal property of Proposition 20.)
(e) We write . Deduce from (d) a canonical morphism of onto , which is a covering mapping. Show, by the example , that is not in general an isomorphism.
Solution
No solution has been written yet.