Bourbaki

Exercise 16, § 6

Lie Groups and Lie Algebras, III, 386

Bourbaki marks this one as harder than the rest.

(a) Let gg be a complex Lie algebra. Let g‾\overline{g} be the complex Lie algebra derived from gg using the automorphism λ↦λ‾\lambda \mapsto \overline{\lambda} of C\mathbf{C}. Let g0g_0 be the real Lie algebra derived from gg by restriction of scalars. Let g′⊃g0g' \supset g_0 be the complex Lie algebra g0⊗RCg_0 \otimes_{\mathbf{R}} \mathbf{C}. For all x∈gx \in g, we write

f(x)=12(x⊗1−(ix)⊗i)∈g′,g(x)=12(x⊗1+(ix)⊗i)∈g′. f(x) = \frac{1}{2}(x \otimes 1 - (ix) \otimes i) \in g', \qquad g(x) = \frac{1}{2}(x \otimes 1 + (ix) \otimes i) \in g'.

Show that ff (resp. gg) is an isomorphism of gg (resp. gˉ\bar{g}) onto an ideal mm (resp. nn) of g′g' and that the ideals m,nm, n are supplementary in g′g'. This defines projectors of g′g' onto m,nm, n. Show that, for all x∈gx \in g, f(x)=p(x)f(x) = p(x), g(x)=q(x)g(x) = q(x).

(b) Suppose that gg is finite-dimensional. Let GG be the simply connected complex Lie group with Lie algebra gg. Let G‾\overline{G} be the conjugate complex Lie group and G0G_0 the underlying real Lie group. Then L(G‾)=gˉL(\overline{G}) = \bar{g} and L(G0)=g0L(G_0) = g_0. Let MM (resp. NN) be the simply connected complex Lie group with Lie algebra mm (resp. nn). Then ff defines an isomorphism ϕ\phi of GG onto MM, gg defines an isomorphism γ\gamma of G‾\overline{G} onto NN and the simply connected complex Lie group G′G' with with Lie algebra g′g' is identified with M×NM \times N. Show that the real integral subgroup of G′G' with Lie algebra g0g_0 is closed and simply connected and is identified with G0G_0. The restriction to G⊂M×NG \subset M \times N of pr1\mathrm{pr}_1 (resp. pr2\mathrm{pr}_2) is the isomorphism ϕ\phi (resp. γ\gamma) of GG (resp. G‾\overline{G}) onto MM (resp. NN).

(c) Deduce from (b) and Remark 2 of no. 10 that G′G', with the canonical injection of G0G_0 into G′G', is the universal complexification of G0G_0.

(d) Let HH be a connected complex Lie group with Lie algebra gg, H‾\overline{H} the conjugate complex Lie group and H0H_0 the underlying real Lie group, such that GG is the universal covering space of HH. Let KK be the (discrete) kernel of the canonical morphism of GG onto HH. Show that KK is a central subgroup of G′G'. The canonical injection of G0G_0 into G′G' therefore defines an injection ii of H0H_0 into G′/NG'/N. Show that (G′/N,i)(G'/N, i) is the universal complexification of H0H_0. (Note that this ordered pair has the universal property of Proposition 20.)

(e) We write G′/N=(H0)cG'/N = (H_0)_c. Deduce from (d) a canonical morphism ψ\psi of (H0)c(H_0)_c onto H×H‾H \times \overline{H}, which is a covering mapping. Show, by the example H=C∗H = \mathbf{C}^*, that ψ\psi is not in general an isomorphism.

Solution

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Transcribed from the printed volume. Not translated.