Bourbaki

Exercise 13, § 1

Lie Groups and Lie Algebras, IV

Bourbaki marks this one as harder than the rest.

Let (W,S)(W, S) be a Coxeter system. For s,s′∈Ss, s' \in S, define the sequence a(s,s′)\mathbf{a}(s, s') by means of the following rules:

(i) if ss′ss' is of infinite order, a(s,s′)\mathbf{a}(s, s') is the empty sequence; (ii) if ss′ss' is of finite order mm the sequence a(s,s′)\mathbf{a}(s, s') is of length mm and its even (resp. odd) numbered terms are equal to s′s' (resp. ss).

Denote by a(s,s′)a(s, s') the product of the sequence a(s,s′)\mathbf{a}(s, s').

a) Show that the generating set SS and the relations s2=1s^2 = 1 and a(s,s′)=a(s′,s)\mathbf{a}(s, s') = \mathbf{a}(s', s) form a presentation of the group WW.

b) Let qq be an integer ⩾1\geqslant 1. Let Σq\Sigma_q be the set of sequences of qq elements of SS and let RqR_q be the smallest equivalence relation on Σq\Sigma_q for which sequences of the form (A,a(s,s′),B)(A, \mathbf{a}(s, s'), B) and (A,a(s′,s),B)(A, \mathbf{a}(s', s), B) (where s,s′∈Ss, s' \in S and AA and BB are sequences of elements of SS) are equivalent. Let Σqr\Sigma_q^r be the set of sequences s=(s1,…,sq)s = (s_1, \ldots, s_q) such that w(s)=s1…sqw(s) = s_1 \ldots s_q is of length qq. Show that sequences s,s′∈Σqrs, s' \in \Sigma_q^r are equivalent modulo RqR_q if and only if w(s)=w(s′)w(s) = w(s') (argue by induction on qq and apply Prop. 5 of no. 5).

c) Show that a sequence s∈Σqs \in \Sigma_q does not belong to Σqr\Sigma_q^r if and only if ss is equivalent modulo RqR_q to a sequence in which two consecutive terms are equal. (Argue by induction on qq and reduce to the case of a sequence (s1,…,sq)(s_1, \ldots, s_q) which does not belong to Σqr\Sigma_q^r but which is such that (s1,…,sq−1)(s_1, \ldots, s_{q-1}) and (s2,…,sq)(s_2, \ldots, s_q) belong to Σq−1r\Sigma_{q-1}^r; use Exerc. 1 to show that s1…sq−1=s2…sqs_1 \ldots s_{q-1} = s_2 \ldots s_q and apply b).)

Solution

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Transcribed from the printed volume. Not translated.