Bourbaki

Exercise 15, § 1

Lie Groups and Lie Algebras, IV

⁷ Let AA be a set and C\mathscr{C} a subset of P(A)\mathfrak{P}(A). The elements of C\mathscr{C} are called the chambers of AA and a subset FF of a chamber CC is called a facet, the codimension of FF in CC being the cardinal of C−FC - F. A facet FF is said to be a panel of CC if FF is of codimension 1 in CC. Two chambers CC and C′C' are said to be adjoining

⁷ Exercises 15 to 24, as well as Exercises 3 to 17 of § 2, are hitherto unpublished and were communicated to us by J. Tits.

if they have a common panel F: then either C = C' or F = C ∩ C'. A gallery of length n is a sequence Γ=(C0,C1,…,Cn)\Gamma = (C_0, C_1, \ldots, C_n) of n+1n + 1 chambers such that CiC_i and Ci+1C_{i+1} are adjoining for 0≤i≤n−10 \leq i \leq n - 1. Then C0C_0 and CnC_n are called the ends of Γ\Gamma. The gallery Γ\Gamma is called injective if Ci≠Ci+1C_i \neq C_{i+1} for 0≤i≤n−10 \leq i \leq n - 1 and is called minimal if there is no gallery with the same ends and length < n.

The set A (together with C\mathscr{C}) is a building if every element of A belongs to at least one chamber and if any two chambers are the ends of a gallery. The distance between two chambers C and C' is the length d(C,C′)d(C, C') of a minimal gallery with ends C and C'.

A sub-building of a building A is a subset D of A such that D together with C∩P(D)\mathscr{C} \cap \mathfrak{P}(D) is a building.

a) Show that if A is a building, a facet has the same codimension in every chamber containing it; this allows us to speak of the codimension of a facet and of a panel of A without reference to a particular chamber. A morphism of a building B to A is a map ff from B to A such that the restriction of ff to every chamber C of B is a bijection from C to a chamber f(C)f(C) of A. Show that the image under ff of a facet of B is a facet of the same codimension.

b) A building is called an apartment if every panel is contained in exactly two chambers. Show that if A is an apartment, every automorphism of A (i.e. every permutation of A preserving C\mathscr{C}) that leaves fixed all the points of a chamber is the identity. More generally, let φ\varphi be an endomorphism of A and let C be a chamber of A such that φ(a)=a\varphi(a) = a for all a∈Ca \in C. Let (C,C1,…,Cn)(C, C_1, \ldots, C_n) be a gallery of A. Show that, either the gallery (C,φ(C1),…,φ(Cn))(C, \varphi(C_1), \ldots, \varphi(C_n)) is not injective, or φ(a)=a\varphi(a) = a for all aa belonging to the union of the CiC_i.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.