Exercise 15, § 1
Lie Groups and Lie Algebras, IV
⁷ Let be a set and a subset of . The elements of are called the chambers of and a subset of a chamber is called a facet, the codimension of in being the cardinal of . A facet is said to be a panel of if is of codimension 1 in . Two chambers and are said to be adjoining
⁷ Exercises 15 to 24, as well as Exercises 3 to 17 of § 2, are hitherto unpublished and were communicated to us by J. Tits.
if they have a common panel F: then either C = C' or F = C ∩ C'. A gallery of length n is a sequence of chambers such that and are adjoining for . Then and are called the ends of . The gallery is called injective if for and is called minimal if there is no gallery with the same ends and length < n.
The set A (together with ) is a building if every element of A belongs to at least one chamber and if any two chambers are the ends of a gallery. The distance between two chambers C and C' is the length of a minimal gallery with ends C and C'.
A sub-building of a building A is a subset D of A such that D together with is a building.
a) Show that if A is a building, a facet has the same codimension in every chamber containing it; this allows us to speak of the codimension of a facet and of a panel of A without reference to a particular chamber. A morphism of a building B to A is a map from B to A such that the restriction of to every chamber C of B is a bijection from C to a chamber of A. Show that the image under of a facet of B is a facet of the same codimension.
b) A building is called an apartment if every panel is contained in exactly two chambers. Show that if A is an apartment, every automorphism of A (i.e. every permutation of A preserving ) that leaves fixed all the points of a chamber is the identity. More generally, let be an endomorphism of A and let C be a chamber of A such that for all . Let be a gallery of A. Show that, either the gallery is not injective, or for all belonging to the union of the .
Solution
No solution has been written yet.