Bourbaki

Exercise 6, § 4

Lie Groups and Lie Algebras, V

Bourbaki marks this one as harder than the rest.

a) Let mm be an integer ≥2\geq 2, or +∞+\infty. Show that 4cos⁡2πm∈Z4 \cos^2 \frac{\pi}{m} \in \mathbf{Z} is equivalent to m∈{2,3,4,6,+∞}m \in \{2, 3, 4, 6, +\infty\}.

b) Let Γ\Gamma be a lattice in EE, i.e. a discrete subgroup of EE of rank dim⁡E\dim E. Show that, if Γ\Gamma is stable under WW, the integers m(s,s′)m(s, s') for s≠s′s \neq s' all belong to the set {2,3,4,6,+∞}\{2, 3, 4, 6, +\infty\}. (Observe that Tr(σ(w))∈Z\mathrm{Tr}(\sigma(w)) \in \mathbf{Z} for all w∈Ww \in W; apply this result to w=ss′w = ss', and use a) above.)

c) Assume that m(s,t)∈{2,3,4,6,,+∞}m(s, t) \in \{2, 3, 4, 6, , +\infty\} for s≠t∈Ss \neq t \in S. A family (xs)s∈S(x_s)_{s \in S} of positive real numbers is called radical if it satisfies the following conditions:

m(s,t)=3  ⟹  xs=xtm(s,t)=4  ⟹  xs=2.xt or xt=2.xsm(s,t)=6  ⟹  xs=3.xt or xt=3.xsm(s,t)=+∞  ⟹  xs=xtor xs=2xt or xt=2xs. \begin{align*} m(s, t) = 3 &\implies x_s = x_t \\ m(s, t) = 4 &\implies x_s = \sqrt{2}.x_t \text{ or } x_t = \sqrt{2}.x_s \\ m(s, t) = 6 &\implies x_s = \sqrt{3}.x_t \text{ or } x_t = \sqrt{3}.x_s \\ m(s, t) = +\infty &\implies x_s = x_t \quad \text{or } x_s = 2x_t \text{ or } x_t = 2x_s. \end{align*}

If (xs)s∈S(x_s)_{s \in S} is such a family, put αs=xses\alpha_s = x_s e_s. Show that

σs(αt)=αt−n(s,t)αs,with n(s,t)∈Z. \sigma_s(\alpha_t) = \alpha_t - n(s, t)\alpha_s, \quad \text{with } n(s, t) \in \mathbf{Z}.

Deduce that the lattice Γ\Gamma with basis (αs)s∈S(\alpha_s)_{s \in S} is stable under WW.

d) With the assumptions in c), suppose that the graph of (W,S)(W, S) is a forest. Show that in that case there exists at least one radical family (xs)(x_s). (Argue by induction on Card(S); apply the induction hypothesis to S - {s_0}, where s_0 is a terminal vertex of the graph of S.)

e) With the assumptions in c), suppose that the graph of (W, S) is a circuit. Let n_4 (resp. n_6) be the number of arrows {s, t} of this graph whose coefficient m(s, t) is equal to 4 (resp. 6). Show that a radical family exists if and only if n_4 and n_6 are both even. If this condition is not satisfied, show that no lattice of E is stable under W (if S = {s_1, ..., s_n}, with s_i linked to s_{i+1} for 1 \leq i \leq n-1, and s_n linked to s_1, put c = s_1 ... s_n and show that Tr(\sigma(c)) is not an integer).

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.