Bourbaki

Exercise 4, § 6

Lie Groups and Lie Algebras, V

With the assumptions and notation of no. 1, denote by nijn_{ij} the order of sHisHjs_{H_i} s_{H_j}, and put aij=−2cos⁡πnija_{ij} = -2 \cos \frac{\pi}{n_{ij}}. Then aii=2a_{ii} = 2 and aij≤0a_{ij} \leq 0 if i≠ji \neq j, cf. § 3. Show12^{12}, by using the method of the preceding exercise, that

∣Xa12…a1la21X…a2l⋮⋮⋱⋮al1al2…X∣=∏i=1l(X−2cos⁡(πmi/h)), \begin{vmatrix} X & a_{12} & \ldots & a_{1l} \\ a_{21} & X & \ldots & a_{2l} \\ \vdots & \vdots & \ddots & \vdots \\ a_{l1} & a_{l2} & \ldots & X \end{vmatrix} = \prod_{i=1}^{l} (X - 2 \cos(\pi m_i / h)),

where m1,…,mlm_1, \ldots, m_l are the exponents of W.

12^{12}For more details, see: H. S. M. COXETER, The product of the generators of a finite group generated by reflections, Duke Math. Journal., v. XVIII (1951), p. 765-782.

Solution

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Transcribed from the printed volume. Not translated.