Bourbaki

Exercise 5, § 1

Lie Groups and Lie Algebras, VI

Let R be an irreducible root system. For any β∈R\beta \in R, 16\gamma(R) = (\sum_{\alpha \in R} n(\alpha, \beta)^2)(\sum_{\alpha \in R} n(\beta, \alpha)^2)

and consequently γ(R)=γ(λR)\gamma(R) = \gamma(\lambda R) for any non-zero scalar λ\lambda. (Use formulas (17) and (19) of no. 12.)

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.