Bourbaki marks this one as harder than the rest.
a) Let a be a nilpotent Lie algebra, x∈a,n∈N,p∈N. There exists l∈N such that xly1...yn∈U(a)xp for all y1,...,yn∈a.
b) Let λ,μ∈h∗, and α∈B be such that
Z(sαμ−ρ)⊂Z(μ−ρ)⊂Z(λ−ρ)
Assume that λ∈P. Let p=λ(Hα)∈Z. Show that:
b1) If p≤0, then Z(λ−ρ)⊂Z(sαλ−ρ).
b2) If p>0, then Z(sαμ−ρ)⊂Z(sαλ−ρ)⊂Z(λ−ρ).
(Use a), and §6, Cor. 1 of Prop. 6.)
c) Let λ∈h∗,α∈R, and m=λ(Hα). Assume that m∈N. Show that
Z(sαλ−ρ)⊂Z(λ−ρ)
(Prove this first for λ∈P by using b), and then in the general case by using Exerc. 12d).)17
Nothing.