Bourbaki

Exercise 18, § 9

General Topology, I, 145

Bourbaki marks this one as harder than the rest.

A Hausdorff space XX is said to be absolutely closed if it has the following property: for every homeomorphism ff of XX onto a subspace of a Hausdorff space X′X', f(X)f(X) is closed in X′X'. Every compact space is absolutely closed.

a) Show that the following conditions are equivalent:

(AF') The space XX is absolutely closed.

(AF'') Every filter base on XX which consists of open sets has at least one cluster point.

(AF''') Every family of closed subsets of XX whose intersection is empty contains a finite subfamily such that the interiors of the subsets in this subfamily have an empty intersection.

(AF''') Every open covering of XX contains a finite subfamily whose closures cover XX.

b) Let X be a Hausdorff space and U a dense open subset of X. Suppose that every filter base on U which consists of open sets has at least one cluster point in X. Show that under these conditions X is absolutely closed. In particular, if A is an open subset of an absolutely closed space X, then A‾\overline{A} is absolutely closed.

c) Let X be an absolutely closed space and let ff be a continuous mapping of X into a Hausdorff space X′X'. Show that f(X)f(X) is an absolutely closed subspace of X′X'.

d) Show that the product of two absolutely closed spaces is absolutely closed (argue as in Proposition 17 of no. 10).

Solution

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