Exercise 4, § 2
General Topology, III, 299
Bourbaki marks this one as harder than the rest.
a) In a semi-topological group , the intersection of the neighbourhoods of which are both open and closed is a closed subgroup which is invariant under all automorphisms of (remark that there can be no partition of into two open and closed subsets, each of which meets ).
b) On the set of all subgroups of , define a mapping as follows: if is any subgroup of , then is the subgroup of which is the intersection of all the simultaneously open and closed neighbourhoods of in . In the set , ordered by the relation , consider the chain of with respect to the mapping (Set Theory, Chapter III, § 2, Exercise 6); show that the smallest subgroup of is the connected component of in (remark that this smallest subgroup must be connected).
Solution
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