Exercise 22, § 6
General Topology, III, 321
Bourbaki marks this one as harder than the rest.
In a division ring endowed with a Hausdorff topology compatible with the ring structure of , a set containing is said to be retrobounded if is bounded. is said to be locally retrobounded if there is a fundamental system of retrobounded neighbourhoods of in with respect to .
a) A locally retrobounded topology is locally bounded, and is a minimal element in the set of all Hausdorff topologies compatible with the ring structure of ; also is compatible with the division ring structure of [use Exercise 19 a)].
b) Suppose from now on, in this exercise, that is a locally retrobounded topology on . Show that, for every neighbourhood of in , is uniformly continuous on . Hence show that the completion of is a topological division ring whose topology is locally retrobounded.
c) Every neighbourhood of in (with respect to ) contains a neighbourhood of such that is not empty. Show that the three uniformities on , induced by the additive uniformity and the two multiplicative uniformities on , coincide. Deduce that, if is complete, then is complete with respect to either multiplicative uniformity.
d) Show that if is an element of then exactly one of the following three statements is true: (i) is topologically nilpotent; (ii) is topologically nilpotent; (iii) the sequence is bounded. [By considering a bounded neighbourhood of such that
(Exercise 20 d)), show that if o is a cluster point of the sequence , then is topologically nilpotent.] If contains non-zero topologically nilpotent elements, show that the set , consisting of o and all such that is not topologically nilpotent, is a bounded neighbourhood of o in which is invariant under all inner automorphisms [use Exercise 21 b)]; then contains all bounded neighbourhoods of o such that ; the set of such neighbourhoods which are invariant under all inner automorphisms has a greatest element, which coincides with if the commutator subgroup of is bounded, in particular if is a field.
e) If is a bounded symmetric neighbourhood of o in such that , then there exists such that . Let be such that , and suppose that the sequence is bounded. Show that the set of all such that is contained in the union of the sets is a bounded neighbourhood of o such that and .
f) Suppose that contains no non-zero topologically nilpotent elements. Show that there is a bounded neighbourhood of o in which is a subring of such that . [Begin with a bounded neighbourhood of o such that (see e)]; if is such that , observe that the ring generated by is contained in the union of the sets .
Solution
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