Bourbaki

Exercise 6, § 6

General Topology, IV, 394

Let ff be a real-valued function defined on a topological space XX. The number (finite or infinite)

ω(a;f)=lim⁡x→asup⁡f(x)−lim⁡x→ainf⁡f(x) \omega(a; f) = \lim_{x \to a} \sup f(x) - \lim_{x \to a} \inf f(x)

is called the oscillation of ff at a∈Xa \in X, whenever the right-hand side is defined.

a) Show that x→ω(x;f)x \to \omega(x; f) is upper semi-continuous on the subspace AA of XX where this mapping is defined.

b) If ff is finite on XX, then A=XA = X and for each a∈Xa \in X we have

ω(a;f)=lim⁡(x,y)→(a,a)sup⁡(f(x)−f(y)). \omega(a; f) = \lim_{(x, y) \to (a, a)} \sup (f(x) - f(y)).

c) Let ff be a lower semi-continuous finite real-valued function on XX. Show that if, at a point a∈Xa \in X, ω(a;f)\omega(a; f) has a finite value, then

lim inf⁡x→aω(x;f)=0. \liminf_{x \to a} \omega(x; f) = 0.
[Assuming the result false, show that there would exist points xx arbitrarily near to aa such that f(x)f(x) is as large as we please].

d) For each rational number r=p/qr = p/q in irreducible form (with q>0q > 0), put f(r)=qf(r) = q. Show that ff is lower semi-continuous on Q\mathbf{Q}, but that at each point r∈Qr \in \mathbf{Q} we have ω(r;f)=+∞\omega(r; f) = +\infty.

Solution

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Transcribed from the printed volume. Not translated.