Bourbaki

Exercise 9, § 6

General Topology, IV, 396

Bourbaki marks this one as harder than the rest.

a) Let XX and YY be two Hausdorff spaces and let π:X→Y\pi : X \to Y be a proper mapping (Chapter I, § 10, no. 1). Let gg be a lower semi-continuous real-valued function on XX. For each y∈Yy \in Y, let f(y)f(y) be the greatest lower bound of gg in the set π‾−1(y)\overline{\pi}^{-1}(y) [thus f(y)=+∞f(y) = +\infty if π‾−1(y)=∅\overline{\pi}^{-1}(y) = \varnothing]. Show that ff is lower semi-continuous on YY. [Use the fact that π(X)\pi(X) is closed, that π‾−1(y)\overline{\pi}^{-1}(y) is compact for all y∈π(X)y \in \pi(X), and that every neighbourhood of π‾−1(y)\overline{\pi}^{-1}(y) contains a neighbourhood which is saturated with respect to the equivalence relation π(x)=π(x′)\pi(x) = \pi(x').]

b) Let gg be the continuous function ∣x1x2−1∣|x_1 x_2 - 1| defined on R×]0,+∞[\mathbf{R} \times ]0, +\infty[, and for each x1∈Rx_1 \in \mathbf{R} let f(x1)=inf⁡x2>0g(x1,x2)f(x_1) = \inf_{x_2 > 0} g(x_1, x_2). Show that ff is not lower semi-continuous.

Solution

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