Bourbaki

Exercise 16, § 7

General Topology, IV, 400

Let (un)(u_n) be a sequence of finite real numbers such that the series whose general term is unu_n is convergent but not absolutely convergent. Show that there exists a permutation σ\sigma of N\mathbf{N} satisfying the condition of Chapter III, § 5, Exercise 6 a) but such that the series whose general term is uσ−1(n)u_{\sigma^{-1}(n)} is not convergent. [Let h,k,mh, k, m be three integers with the following properties : if p1,…,prp_1, \ldots, p_r are the integers nn such that h≤n<h+mh \leq n < h + m and un≥0u_n \geq 0, then up1+⋯+upr>2u_{p_1} + \cdots + u_{p_r} > 2 and h+m<k−rh + m < k - r; moreover if μ,ν\mu, \nu are any integers such that h+m≤μ≤νh + m \leq \mu \leq \nu, then ∣∑n=μνun∣≤1\left| \sum_{n=\mu}^{\nu} u_n \right| \leq 1. Put s=m−rs = m - r and let q1,…,qsq_1, \ldots, q_s denote the integers nn such that h≤n<h+mh \leq n < h + m and un<0u_n < 0. Consider the permutation π\pi of the interval [h,k+s][h, k + s] of N\mathbf{N} such that π(pi)=k−i+1\pi(p_i) = k - i + 1 for 1≤i≤r1 \leq i \leq r, π(qj)=k+j\pi(q_j) = k + j for 1≤j≤s1 \leq j \leq s, π(k+j)=h+s−j\pi(k + j) = h + s - j for 1≤j≤s1 \leq j \leq s, π(k−i+1)=h+s+i−1\pi(k - i + 1) = h + s + i - 1 for 1≤i≤r1 \leq i \leq r and finally π(n)=n\pi(n) = n for h+m≤n≤k−rh + m \leq n \leq k - r; show that we have

∣∑i=hkui−∑i=hkuπ−1(i)∣≥1. \left| \sum_{i=h}^k u_i - \sum_{i=h}^k u_{\pi^{-1}(i)} \right| \geq 1.

Solution

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