Bourbaki

Exercise 4, § 7

General Topology, IV, 398

Let (an)(a_n) be any sequence of finite real numbers ≥0\geq 0. Show that the sequence (an(1+a1)(1+a2)…(1+an))\left( \frac{a_n}{(1 + a_1)(1 + a_2) \ldots (1 + a_n)} \right) is summable in R\mathbf{R} (express each term of this sequence as a difference).

Solution

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Transcribed from the printed volume. Not translated.