Exercise 7, § 7 General Topology, IV, 398 Show that, for each integer p>1p > 1p>1, ∑n=1∞(−1)n−1np=(1−21−p)∑n=1∞1np. \sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n^p} = (1 - 2^{1-p}) \sum_{n=1}^{\infty} \frac{1}{n^p}. n=1∑∞np(−1)n−1=(1−21−p)n=1∑∞np1. Solution No solution has been written yet.