Bourbaki

Exercise 8, § 1

General Topology, IX

Bourbaki marks this one as harder than the rest.

Let XX be a completely regular space and let βX\beta X be its Stone-Čech compactification.

a) A filter F\mathscr{F} on XX is said to be completely regular if F\mathscr{F} has a base B\mathscr{B} consisting of open sets such that for each set A∈BA \in \mathscr{B} there exists a set B∈BB \in \mathscr{B} contained in AA, and a continuous mapping f:X→[0,1]f : X \to [0, 1] which is equal to 0 on BB and 1 on C‾A\overline{C}A. A completely regular filter is said to be maximal if there exists no strictly finer completely regular filter. Show that, if F\mathscr{F} is any completely regular filter on EE, there is a maximal completely regular filter finer than F\mathscr{F} (use Zorn’s lemma).

b) A completely regular filter F\mathscr{F} is maximal if and only if, for each pair of open sets A,BA, B of XX such that B⊂AB \subset A and such that there is a continuous mapping of XX into [0,1][0, 1] which is equal to 0 on BB and equal to 1 on C‾A\overline{C}A, we have either A∈FA \in \mathscr{F}, or else A∉FA \notin \mathscr{F} there is a set of F\mathscr{F} which does not meet BB (if all the sets of F\mathscr{F} meet BB, consider the filter generated by the sets of F\mathscr{F} and the sets fˉ−1([0,a[),\bar{f}^{-1}([0, a[), where a∈]0,1[a \in ]0, 1[).

c) Show that every maximal completely regular filter F\mathscr{F} is a Cauchy filter on XX with respect to the uniformity induced by that of βX\beta X [show that each continuous mapping f:X→[0,1]f : X \to [0, 1] has a limit with respect to F\mathscr{F}, by arguing by reductio ad absurdum and using b)].

d) Two distinct maximal completely regular filters F,F′\mathscr{F}, \mathscr{F}' cannot converge to the same point of βX\beta X [observe that by b) there exists an open set A∈FA \in \mathscr{F} and an open set A′∈F′A' \in \mathscr{F}' such that A∩A′=∅A \cap A' = \varnothing; then argue by contradiction, using axiom (OIV)(O_{IV})].

e) The trace on XX of the neighbourhood filter of any point x0∈βXx_0 \in \beta X is a maximal completely regular filter B\mathscr{B} (argue by contradiction, using the definitions of a completely regular filter and of the neighbourhood filter of a point in βX\beta X.

Solution

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Transcribed from the printed volume. Not translated.