Exercise 13, § 2
General Topology, IX
a) On the set of real numbers, consider the topology defined as follows: for each , denotes the union of the intervals and ; is the topology for which the form a fundamental system of neighbourhoods of as runs through the set of real numbers . Let be the space obtained by endowing the interval with the topology induced by . Show that is compact. (Consider a filter on ; if is a cluster point of with respect to the topology of the real line, show that either or is a cluster point of with respect to .)
b) Every point of has a countable fundamental system of neighbourhoods, and has a countable dense subset, but is not metrizable (show that its topology has no countable base).
c) Let be an open subset of . Show that is the union of a countable family of open intervals contained in , the intervals , a subset of the set of left-hand points of the intervals and , and possibly the point . Hence show that is the union of a countable family of closed subsets of .
d) Let be the set , where is the interval of ; let denote () and let denote the bijection of onto . For each , let denote the set of subsets consisting only of , and let denote the set of subsets of the form , where and runs through a fundamental system of neighbourhoods of in . Show that for each , is a fundamental system of neighbourhoods of for a topology on . Endowed with this topology, is compact and every point of has a countable fundamental system of neighbourhoods, but has no countable dense subset. Every closed subset of contained in is finite; hence show that the compact subset of has no countable fundamental system of neighbourhoods. If is the equivalence relation on whose classes are the set and the points of , is closed and every equivalence class mod is compact, but there is a point in which has no countable fundamental system of neighbourhoods [cf. § 4, Exercise 24 a)].
Solution
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