Bourbaki

Exercise 22, § 2

General Topology, IX

Bourbaki marks this one as harder than the rest.

Let XX be a Hausdorff topological space with a countable base (Un)(U_n), and let RR be a Hausdorff equivalence relation on XX such that every point of X/RX/R has a countable fundamental system of neighbourhoods. Show that the topology of X/RX/R has a countable base. [Let φ:X→X/R\varphi : X \to X/R be the canonical mapping, and show that the interiors of finite unions of sets φ(Un)\varphi(U_n) form a base of the topology of X/RX/R: if VV is a neighbourhood of a point z∈X/Rz \in X/R, and (Wk)(W_k) is a sequence of sets belonging to the base (Un)(U_n), contained in φ−1(V)‾\overline{\varphi^{-1}(V)} and covering φ−1(z)‾\overline{\varphi^{-1}(z)}, show that there is a finite number of indices kk such that the union of the φ−1(Wk)‾\overline{\varphi^{-1}(W_k)} is a neighbourhood of zz. Argue by contradiction: if this statement were false we could construct a sequence (γn)(\gamma_n) of distinct points of X/RX/R, tending to zz and such that γn\gamma_n did not belong to the union of the φ(Wk)\varphi(W_k) for k≤nk \leq n; then show that the union of the φ−1(γn)‾\overline{\varphi^{-1}(\gamma_n)} would be closed in XX.]

Show that the same conclusion is valid if RR is assumed to be closed and every equivalence class mod RR is compact (similar method).

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.