Bourbaki

Exercise 25, § 2

General Topology, IX

Bourbaki marks this one as harder than the rest.

Let XX be a metrizable space, let βX\beta X be its Stone-Čech compactification (§1§ 1, Exercise 7) and let dd be a bounded metric compatible with the topology of XX. For each x∈Xx \in X, let fx(y)f_x(y) denote the real-valued function obtained by extending y→d(x,y)y \to d(x, y) by continuity to βX\beta X.

a) Show that fx(z)+fy(z)≥d(x,y)f_x(z) + f_y(z) \geq d(x, y) whenever xx and yy are in XX and zz is in βX\beta X. For each y∈βXy \in \beta X other than x∈βXx \in \beta X, show that fx(y)>0f_x(y) > 0.

b) Show that if XX is complete with respect to the metric dd, then XX is the intersection of a sequence of open sets in βX\beta X. [Consider the set GnG_n of all y∈βXy \in \beta X such that fx(y)<1/nf_x(y) < 1/n for at least one point x∈φXx \in \varphi X, and show by using aa that X=⋂nGnX = \bigcap_n G_n.]

c) Conversely, show that if XX is the intersection of a sequence of open sets GnG_n in βX\beta X, there exists a metric d′d' on XX which is compatible with the topology of XX, and with respect to which XX is complete. [Considering only the case in which X≠βXX \neq \beta X, note that βX−X\beta X - X is the union of a family of compact sets Fn=βX−GnF_n = \beta X - G_n; for each nn, let gn(x)=inf⁡y∈Fnfx(y)g_n(x) = \inf_{y \in F_n} f_x(y), and show by using aa that gn(x)>0g_n(x) > 0 for all x∈Xx \in X, and that gng_n is continuous on XX. Finish the proof as in Exercise 16 b) of §1§ 1.]

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.