Bourbaki

Exercise 1, § 6

General Topology, IX

a) Every zero-dimensional space is completely regular. The non-normal locally compact spaces defined in § 4, Exercise 26 b) and § 5, Exercise 15 are zero-dimensional.

b) A topological space XX is said to be strongly zero-dimensional if for each closed subset AA of XX and each neighbourhood UU of AA, there is an open and closed neighbourhood of AA contained in UU. Every strongly zero-dimensional space is normal. A normal space is strongly zero-dimensional if and only if its Stone-Čech compactification (§1§ 1, Exercise 7) is totally disconnected [use Exercise 17 c) of § 4].

c) Let XX be a strongly zero-dimensional Hausdorff space and let (Un)(U_n) be an increasing sequence of non-empty open sets in XX. Show that there exists a sequence (Gn)(G_n) of mutually disjoint sets which are both open and closed in XX, such that Gn⊂UnG_n \subset U_n for each nn, and ⋃nGn=⋃nUn\bigcup_n G_n = \bigcup_n U_n (define the GnG_n by induction). If, moreover, XX is perfectly normal (§4§ 4, Exercise 8), every open set in XX is the union of a countable family of mutually disjoint sets which are both open and closed in XX.

d) Let XX be a normal space which is the union of a sequence (An)(A_n) of strongly zero-dimensional subspaces. Show that XX is strongly zero-dimensional. [Let B,CB, C be two disjoint closed subsets of XX; define by induction two increasing sequences (Gn),(Hn)(G_n), (H_n) of open sets in XX such that G‾n∩H‾n≠∅, An⊂Gn∪Hn, B∩An⊂Gn, C∩An⊂Hn.\overline{G}_n \cap \overline{H}_n \neq \varnothing,\ A_n \subset G_n \cup H_n,\ B \cap A_n \subset G_n,\ C \cap A_n \subset H_n.]

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.