Bourbaki

Exercise 16, § 6

General Topology, IX

Bourbaki marks this one as harder than the rest.

Let X,X′X, X' be two metrizable spaces. A mapping f:X→X′f : X \to X' is said to be a Borel mapping if, for each closed subset F′F' of X′X', f−1(F′)‾\overline{f^{-1}(F')} is a Borel set in XX. For each even (resp. odd) countable ordinal α\alpha, ff is said to be of class α\alpha if, for each closed subset F′F' of X′X', f−1(F′)‾\overline{f^{-1}(F')} belongs to Fα(X)\mathfrak{F}_\alpha(X) [resp. Gα(X)\mathfrak{G}_\alpha(X)] (Exercise 4); then, for each open set G′G' in X′X', f−1(G′)‾\overline{f^{-1}(G')} belongs to Gα(X)\mathfrak{G}_\alpha(X) [resp. Fα(X)\mathfrak{F}_\alpha(X)]. The Borel mappings of class 0 are precisely the continuous mappings.

a) The characteristic function φA\varphi_A of a subset AA of XX is of class α\alpha if and only if A∈Fα∩GαA \in \mathfrak{F}_\alpha \cap \mathfrak{G}_\alpha.

b) Let f:X→X′f : X \to X' be a mapping of class α\alpha. Show that for every subset B′∈Fβ(X′)B' \in \mathfrak{F}_\beta(X') [resp. B′∈Gβ(X′)B' \in \mathfrak{G}_\beta(X')], f−1(B′)‾\overline{f^{-1}(B')} belongs to Fα+β(X)\mathfrak{F}_{\alpha+\beta}(X) [resp. Gα+β(X)\mathfrak{G}_{\alpha+\beta}(X)]. (Use transfinite induction on β\beta.)

c) Let f:X→X′f : X \to X' be a mapping of class α\alpha and let g:X′→X′′g : X' \to X'' be a mapping of class β\beta, where X′′X'' is a third metrizable space. Show that g∘fg \circ f is a Borel mapping of class α+β\alpha + \beta.

d) For each even (resp. odd) countable ordinal α\alpha, let (An)(A_n) be a sequence of subsets of XX which belong to Gα\mathfrak{G}_\alpha (resp. Fα\mathfrak{F}_\alpha) and which cover XX. If a mapping f:X→X′f : X \to X' is such that f∣Anf|A_n is of class α\alpha for each nn, then ff is of class α\alpha. Give the analogous result for a finite sequence of subsets of XX which belong to Fα\mathfrak{F}_\alpha (resp. Gα\mathfrak{G}_\alpha) and cover XX.

Solution

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