Let f(z)=zn+a1zn−1+⋯+an−1z+an be a polynomial of degree n with complex coefficients and put f(z)=∏i=1n(z−zi). Let r0=supi∣zi∣.
a) Show that if the real number r>0 is such that
rn≤∣a1∣rn−1+∣a2∣rn−2+⋯+∣an−1∣r+∣an∣, then
r0≤r, and deduce that
r0≤sup(1,k=1∑n∣ak∣).
b) Let (λi)1≤i≤n be a finite sequence of n real numbers >0 such that ∑i=1nλi−1=1. Show that r0≤supk(λk∣ak∣)1/k [use a)].
c) Deduce from a) that, if the coefficients ai are all non-zero, we have
r0≤sup(2∣a1∣,2a1a2,…,2an−2an−1,an−1an).
d) Deduce from a) that
r0≤∣a1−1∣+∣a2−a1∣+⋯+∣an−1−an∣+∣an∣ [consider the polynomial
(z−1)f(z)]. Hence show that, if the
ai are all real and
>0, we have
r0≤sup(a1,a1a2,…,an−2an−1,an−1an).