Exercise 13, § 4
General Topology, X
Bourbaki marks this one as harder than the rest.
Let be a compact space and let denote the normed algebra . For each subset of , let denote the set of all such that for all . For each subset of , let denote the set of all such that for all .
a) is a closed subspace of and is a closed ideal of . If is the ideal of generated by a subset of , then ; and are order-reversing mappings (with respect to the order relation of inclusion), and we have for every unit of ;
for every family of subsets of ; ; for every family of subsets of .
b) Show that if is any ideal of , then , and that if is any subset of , then . (For the first of these relations, observe that and that we may therefore suppose closed; note that if are two distinct points of , there exists such that , and use Proposition 4 of no. 2. To prove the second relation, use Urysohn's theorem.)
c) Deduce from b) that is a bijection of onto the set of maximal ideals of , which are therefore closed. An ideal of is closed if and only if it is an intersection of maximal ideals. The ring has no radical.
d) Show that the mapping is a bijection of the set of idempotents of onto the set of subsets of which are both open and closed.
A point is isolated if and only if the maximal ideal is principal.
Solution
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