Suppose that C is hereditary. Let E be a module of type C and (Ei)0⩽i⩽n a composition series of E (I, §4, No. 7, p. 41). For 1⩽i⩽n, the module Ei−1/Ei is of type C, and we have
φ(E)=i=1∑nφ(Ei−1/Ei)
Since C is hereditary, the modules E0/E1 and E1 are of type C, and we have φ(E)=φ(E0/E1)+φ(E1). Since the sequence (Ei+1)0⩽i⩽n−1 is a composition series of E1, Proposition 3 follows by induction on n.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.