Bourbaki

Proposition 6

Tag 00D5, permanent. Cite it as [Bourbaki, Tag 00D5].

Algebra, VIII, p. 189, § 11. Grothendieck Groups

a) The mapping E↦[E]C′E\mapsto [E]'_{\mathscr{C}} from C\mathscr{C} to K′(C)K'(\mathscr{C}) is a weakly additive function of modules.

b) Let G be an abelian group, and let φ:C→G\varphi :\mathscr{C}\rightarrow G be a weakly additive function of modules. There exists a unique group homomorphism u:K′(C)→u: K'(\mathscr{C})\rightarrow G such that we have φ(E)=u([E]C′)\varphi (E) =u([E]'_{\mathscr{C}}) for every module E of type C\mathscr{C}.

c) Let E and F be modules of type C\mathscr{C}. We have [E]C′=[F]C′[E]'_{\mathscr{C}}= [F]'_{\mathscr{C}} if and only if there exists a module M of type C\mathscr{C} such that E⊕ME\oplus M is isomorphic to F⊕MF\oplus M.

Assertion a) is obvious. Assertion b) follows from (I, §2, No. 4, p. 19, Theorem 1) and assertion c) from (I, §2, No. 4, p. 18, Proposition 6).

Since the mapping E↦[E]CE\mapsto [E]_{\mathscr{C}} from C\mathscr{C} to K(C)K(\mathscr{C}) is a weakly additive function of modules, we can deduce a homomorphism u:K′(C)→K(C)u: K'(\mathscr{C})\rightarrow K(\mathscr{C}) from it. This homomorphism is surjective but is not always an isomorphism (VIII, p. 191, Remark 2).

Let R′R' be the subgroup of Z(C)\mathbf{Z}^{(\mathscr{C})} generated by the elements of the form rEr_{\mathscr{E}}, where E\mathscr{E} is a split exact sequence of A-modules of type C\mathscr{C}, that is, by the elements of the form cl(E′⊕E′′'\oplus E'')−- cl(E′')−- cl(E′′''), where E′E' and E′′E'' are modules of type C\mathscr{C}. The canonical mapping from C\mathscr{C} to the quotient group Z(C)/R′\mathbf{Z}^{(\mathscr{C})}/R' extends to a group homomorphism v:K′(C)→Z(C)/R′v: K'(\mathscr{C})\rightarrow \mathbf{Z}^{(\mathscr{C})}/R'. This is an isomorphism. Indeed, the canonical mapping from C\mathscr{C} to K′(C)K'(\mathscr{C}) extends to a group homomorphism from Z(C)\mathbf{Z}^{(\mathscr{C})} to K′(C)K'(\mathscr{C}) whose kernel contains R′R', and therefore to a homomorphism v′:Z(C)/R′→K′(C)v':\mathbf{Z}^{(\mathscr{C})}/R'\rightarrow K'(\mathscr{C}) by passing to the quotient; it is clear that vv and v′v' are inverse bijections.

An element of K′(C)K'(\mathscr{C}) is called effective if it is of the form [E]C′[E]'_{\mathscr{C}} for an A-module E of type C\mathscr{C}. The set of effective elements of K′(C)K'(\mathscr{C}) is denoted by K′(C)+K'(\mathscr{C})^+.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

  • I, §2, No. 4, p. 18, Proposition 6 not in this corpus
  • I, §2, No. 4, p. 19, Theorem 1 not in this corpus
  • VIII, p. 191, Remark 2
Transcribed from the printed edition, 2023, Springer Nature. Not translated.