Bourbaki

Proposition 4

Tag 00H5, permanent. Cite it as [Bourbaki, Tag 00H5].

Algebra, VIII, p. 264, § 14. Central Simple Algebras

Let A be a central simple algebra of finite degree over K. Let L be a subalgebra of A, and let L′L' be the commutant of L in A.

a) If L is maximal among the semisimple commutative subalgebras of A, then we have L=L′L = L', and L is a maximal commutative subalgebra of A.

b) If L is maximal among the étale subalgebras of A, then we have L=L′L = L', and L is a maximal commutative subalgebra of A.

We know that the relation L=L′L = L' means that L is a maximal commutative subalgebra of A (VIII, p. 261, Lemma 3, a)). Suppose that L is semisimple, commutative, and distinct from L′L'. By Theorem 5 of VIII, p. 259,L′, L' is semisimple, and L is the commutant of L′L' and therefore the center of L′L'; consequently, L′L' is not commutative. It suffices to prove that there exists a semisimple commutative subalgebra M of A that is distinct from L and contains L and that is étale if L is étale.

By the structure theorem for semisimple rings (VIII, p. 135, Theorem 1), there exist simple rings B1,...,BrB_1, . . . ,B_r and an isomorphism φ\varphi from L′L' to B1×⋯×BrB_1\times \cdots \times B_r. For 1⩽i⩽r1\leqslant i\leqslant r, denote the center of BiB_i by EiE_i; we then have φ(L)=E1×⋯×Er\varphi (L) = E_1\times \cdots \times E_r. Since L′L' is not commutative, we may assume that B1B_1, for example, is not commutative; we therefore have B1≠E1B_1\not= E_1, and, by Lemma 4, there exists a subalgebra M1M_1 of B1B_1 that is commutative, distinct from E1E_1, and étale over E1E_1. Set M=φ−1(M1×E2×⋯×Er)M =\varphi^{-1}(M_1\times E_2\times \cdots \times E_r); it is a semisimple commutative subalgebra of A containing L and distinct from L. Suppose that L is étale over K; let us prove that M is étale. The extensions EiE_i of K are separable (V, §6, No. 4, p. 30, Proposition 3). Moreover, since the E1E_1-algebra M1M_1 and the K-algebra E1E_1 are étale, the K-algebra M1M_1 is also étale (V, §6, No. 5, p. 32, Corollary 2). Thus the K-algebra M1×E2×⋯×ErM_1\times E_2\times \cdots \times E_r is étale, and therefore so is M.

Let A be a central simple algebra of finite degree over K. A subalgebra of A that is maximal among the semisimple commutative subalgebras of A is called a maximal semisimple commutative subalgebra of A. By Proposition 4, the term “maximal” refers to the property of being commutative or of being semisimple and commutative. A subalgebra of A that is maximal among the étale subalgebras of A is called a maximal étale subalgebra of A.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Cites

Transcribed from the printed edition, 2023, Springer Nature. Not translated.