Bourbaki

Exercise 15, § 14

Tag 00HQ, permanent. Cite it as [Bourbaki, Tag 00HQ].

Algebra, VIII, p. 273

Bourbaki marks this one as harder than the rest.

Keep the notation of Exercise 14; denote the ring EndD(V)_D(V) by A. Let G be a group of automorphisms of A and G0G_0 the subgroup of elements of G that are inner automorphisms of A. Denote by U(G) the (left and right) D-linear subspace of Ω generated by the semilinear bijections ss of V such that the automorphism a↦sas−1a\mapsto sas^{-1} belongs to G, and denote by U0(G)U_0(G) the Z-linear subspace of A generated by the automorphisms uu of V such that the automorphism a↦uau−1a\mapsto uau^{-1} belongs to G0G_0. These are Z-subalgebras of Ω.

a) Let (sα)(s_{\alpha}) be a basis of U0(G)U_0(G) over Z consisting of elements of S0S_0(G), and let (gβ)β∈G/G0(g_{\beta})_{\beta\in G/G_0} be a system of representatives of the classes (mod G0G_0) in G. For each β∈G/G0\beta \in G/G_0, choose an element uβu_{\beta} of S(G) corresponding to gβg_{\beta}. Prove that the elements sαuβs_{\alpha}u_{\beta} form a (left and right) basis of U(G) over D (use Exercise 14, a)). The degree [U(G) : D] is finite if and only if [U0(G):Z][U_0(G) : Z] and (G:G0)(G : G_0) are finite; if this is the case, then we have [U(G):D]=[U0(G):Z](G:G0)[U(G) : D] = [U_0(G) : Z] (G : G_0).

b) Prove that U0(G)U_0(G) is equal to U(G)∩AU(G)\cap A and that U(G0)=Du0(G)U(G_0) = Du_0(G) is canonically isomorphic to U0(G)⊗ZDU_0(G)\otimes_ZD (use Exercise 14 as well as Exercise 14 of VIII, p. 227). c) An element of U(G) is a semilinear mapping from V to itself if and only if it is of the form λsuβ\lambda su_{\beta} with λ∈D,s∈U0\lambda \in D,s\in U_0(G), and β∈G/G0\beta \in G/G_0 (use a), b), and Exercise 14, a)).

d) Denote the commutant of U(G) in Ω by AGA^G; it is the subring of A consisting of the elements invariant under G. Set ZG=AG∩ZZ^G= A^G\cap Z; it is the subfield of elements of Z invariant under G. Prove that Z and AGA^G are linearly disjoint over ZGZ^G (verify that a basis of AGA^G over ZGZ^G is a free subset of A over Z).

e) Prove that if U0(G)U_0(G) is a simple ring and one of the Z-algebras U0(G)U_0(G) and D has finite degree, then the ring U(G) is quasi-simple (deduce from c) that U(G0)U(G_0) is a simple ring, and apply Exercise 14, c) to a two-sided ideal of U(G) using c)).

f ) Suppose that V and U(G) are finite-dimensional over D and that the ring U0(G)U_0(G) is simple. Prove that the ring A[G] is simple and that we have [A:AG]s=[A : A^G]_s= [U0(G):Z](G:G0)[U_0(G) : Z] (G : G_0) (apply Proposition 12 of VIII, p. 205). Prove that the commutant of AGA^G in Ω (resp. in A) is U(G) (resp. U0(G)U_0(G)) (use Proposition 5 of VIII, p. 139).

g) Deduce that the group of automorphisms of A that fix AGA^G consists of the automorphisms a↦vav−1a\mapsto vav^{-1}, where vv runs through the set of semilinear bijections in U(G). Prove that it is generated by G and the inner automorphisms associated with the invertible elements of U0(G)U_0(G) (use c)).

h) If G=G0G = G_0, then the ring AGA^G contains Z; prove the converse when D is finite-dimensional over Z (use Theorem 4 of VIII, p. 257).

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