For i∈{1,2}, take a group Gi, an abelian group Fi, and a group homomorphism τi from Gi to the automorphism group of Fi. We denote by τ1×τ2:G1×G2→ Aut(F1×F2) the homomorphism defined by
(τ1×τ2)(g1,g2)⋅(f1,f2)=(τ1(g1)⋅f1,τ2(g2)⋅f2)
for g1∈G1,g2∈G2,f1∈F1, and f2∈F2. Let E1=(Γ1,ι1,π1) be a τ1-extension of G1 by F1 and E2=(Γ2,ι2,π2) a τ2-extension of G2 by F2. Then the triple (Γ1×Γ2,ι1×ι2,π1×π2) is a τ1×τ2-extension of G1×G2 by F1×F2; it is called the exterior product of the extensions E1 and E2 and denoted by E1×E2.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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