Bourbaki

Exercise 1, § 16

Tag 00JW, permanent. Cite it as [Bourbaki, Tag 00JW].

Algebra, VIII, p. 324

Let G be a group and Z[G]\mathbf{Z}[G] the algebra of G over Z\mathbf{Z}; we identify G with the canonical basis of Z[G]\mathbf{Z}[G]. Let M be a Z\mathbf{Z}[G]-module, that is, an abelian group endowed with an action of G respecting its group structure. For any integer n⩾0n\geqslant 0, denote by Cn(G,M)C^n(G,M) the group of mappings from GnG^n to M; set Cn(G,M)=0C^n(G,M) = 0 for n<0n <0. Define a homomorphism dn:Cn(G,M)→Cn+1(G,M)d^n: C^n(G,M)\rightarrow C^{n+1}(G,M) by the formula

(dnc)(g0,...,gn)=g0c(g1,...,gn)+∑i=0n−1(−1)i+1c(g0,...,gigi+1,...,gn) (d^nc)(g_0, . . . , g_n) =g_0c(g_1, . . . , g_n) +\sum^{n-1}_{i=0}(-1)^{i+1}c(g_0, . . . , g_ig_{i+1}, . . . , g_n)
+(−1)n+1c(g0,...,gn−1) + (-1)^{n+1}c(g_0, . . . , g_{n-1})

For any integer nn, set Zn(G,M)=Z^n(G,M) = Ker dnd^n and Bn(G,M)=B^n(G,M) = Im dnd^n.

a) Prove that Bn(G,M)B^n(G,M) is contained in Zn(G,M)Z^n(G,M).

Set Hn(G,M)=Zn(G,M)/Bn(G,M)H^n(G,M) = Z^n(G,M)/B^n(G,M). The group H0(G,M)H^0(G,M) is the set of elements of M fixed by the action of G. The group Z1(G,M)Z^1(G,M) is the group of mappings f:G→Mf: G\rightarrow M satisfying f(gg′)=f(g)+gf(g′)f(gg') =f(g) +g f(g'), and B1(G,M)B^1(G,M) is the subgroup of mappings ff for which there exists an m∈Mm\in M such that f(g)=gm−mf(g) =gm-m (cf. I, §6, p. 148, Exercise 7).

b) Let N be a Z\mathbf{Z}[G]-module and u:M→Nu: M\rightarrow N a Z\mathbf{Z}[G]-linear mapping. For every integer nn, the mapping c↦u∘cc\mapsto u\circ c is a homomorphism from Cn(G,M)C^n(G,M) to Cn(G,N)C^n(G,N) that sends Zn(G,M)Z^n(G,M) into Zn(G,N)Z^n(G,N) and Bn(G,M)B^n(G,M) into Bn(G,N)B^n(G,N) and therefore induces a homomorphism from Hn(G,M)H^n(G,M) to Hn(G,N)H^n(G,N) that we denote by Hn(G,u)H^n(G, u) or simply Hn(u)H^n(u). If v:N→Pv: N\rightarrow P is a homomorphism of Z\mathbf{Z}[G]-modules, then we have Hn(v∘u)=Hn(v)∘Hn(u)H^n(v\circ u) = H^n(v)\circ H^n(u).

c) Let 0→M′→ιM→πM′′→00\rightarrow M'\rightarrow^{\iota}M\rightarrow^{\pi}M''\rightarrow 0 be an exact sequence of Z\mathbf{Z}[G]-modules. Let nn be an integer and x′′x'' an element of Hn(G,M′′)H^n(G,M''), the class of an element c′′∈c''\in Zn(G,M′′)Z^n(G,M''). Let c∈Cn(G,M)c\in C^n(G,M) be such that π∘c=c′′\pi \circ c=c''. Prove that there exists an element c′∈Zn+1(G,M′)c'\in Z^{n+1}(G,M') such that ι∘c′=dn(c)\iota \circ c'=d^n(c) and that the class of c′c' in Hn+1(G,M′)H^{n+1}(G,M') depends only on x′′x''; we denote that class by ∂n(x′′)\partial^n(x''). The mapping ∂n:Hn(G,M′′)→Hn+1(G,M′)\partial^n: H^n(G,M'')\rightarrow H^{n+1}(G,M') is a homomorphism (“linking homomorphism”). Prove that the sequence

n′Hn(ι)nHn(π)n′′∂nn+1′n'H^n(\iota )nH^n(\pi )n''\partial^nn+1'

⋯⟶H(G,M)⟶H(G,M)⟶\cdots \longrightarrow H(G,M)\longrightarrow H(G,M)\longrightarrow H (G,M)⟶H(G,M)⟶⋯(G,M)\longrightarrow H(G,M)\longrightarrow \cdots

is exact.

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