Algebra, VIII, p. 324
Let φ:H→G be a group homomorphism, M a Z[G]-module, N a Z[H]-module, and u:M→N a homomorphism of abelian groups. We say that φ and u are compatible if we have u(φ(h)x)=hu(x) for every h∈H and x∈M.
a) For n⩾0, let φn:Hn→Gn be the mapping deduced from φ; if φ and u are compatible, then the homomorphism c↦u∘c∘φn from Cn(G,M) to Cn(H,N) sends Zn(G,M) into Zn(H,N) and Bn(G,M) into Bn(H,N) and therefore induces a homomorphism Hn(φ,u) from Hn(G,M) to Hn(H,N). b) Let ψ:K→H be another group homomorphism, P aZ[K]-module, and v:N→P a homomorphism of abelian groups. If φ and u are compatible, and ψ and v also are, then we have Hn(φ∘ψ,v∘u)=Hn(ψ,v)∘Hn(φ,u).
c) Consider a commutative diagram
0 // M′ // M // M′′ // 0
u′uu′′
0 // N′ // N // N′′ // 0 ,
where the first (resp. second) line is an exact sequence of Z[G]-modules (resp. of Z[H]-modules) and where u′,u,u′′ are compatible with φ. Prove that the diagram
⋯ // Hn(G,M′) // Hn(G,M) // Hn(G,M′′) // Hn+1(G,M′) //⋯
Hn(φ,u′)Hn(φ,u)Hn(φ,u′′)Hn+1(φ,u)
⋯ // Hn(H,N′) // Hn(H,N) // Hn(H,N′′) // Hn+1(H,N′) //⋯
(whose horizontal lines are the long exact sequences defined in Exercise 1, c)) is commutative.
d) Examples: If H = G, then the mapping u is compatible with IdG if and and only if it is Z[G]-linear, and we have Hn(IdG,u) =Hn(G,u). If N is equal to M endowed with the Z[G]-module structure deduced from φ, then the homomorphisms φ and 1M are compatible; we denote by Resq:Hq(G,M)→Hq(H,M) the homomorphism Hq(φ,1M) (“restriction homomorphism”).
e) Let H be a normal subgroup of G, and let MH be the subgroup of M consisting of the elements invariant under H, endowed with the action of G/H deduced from that of G by passing to the quotient. The canonical surjection p:G→ G/H and the canonical injection j:MH→M are compatible; we denote by Infq:Hq(G/H,MH)→Hq(G,M) the homomorphism Hq(p,j) (“inflation homomorphism”). Prove that the sequence
0→H1(G/H,MH)⟶Inf1H1(G,M)⟶Res1H1(H,M)
is exact. If, moreover, H1(H,M) is zero, then the sequence
0→H2(G/H,MH)⟶Inf2H2(G,M)⟶Res2H2(H,M)
is exact.