Bourbaki

Exercise 3, § 18

Tag 00LL, permanent. Cite it as [Bourbaki, Tag 00LL].

Algebra, VIII, p. 359

Bourbaki marks this one as harder than the rest.

Let K be a commutative field. We say that a K-algebra A is algebraic if all its elements are algebraic over K. Every algebra of finite rank is algebraic; every subalgebra and quotient algebra of an algebraic algebra is algebraic. The radical of an algebraic K-algebra is a nil ideal (VIII, p. 166, Exercise 5).

a) Prove that an algebraic algebra is a pseudoregular ring (VIII, p. 178, Exercise 4; observe that for every x∈Ax\in A, there exist an element y∈K[x]y\in K[x] and an integer kk such that xk=xk+1yx^k=x^{k+1}y).

b) Let A be an algebraic K-algebra without any nilpotent elements other than 0. Prove that A is isomorphic to a subalgebra of a product of fields. (Observe that every quotient algebra of A has the same properties. Prove that if A is primitive, then it is a field, by reasoning as in Exercise 2, a). In the general case, use Exercise 12 of VIII, p. 168.)

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