Bourbaki

Proposition 2

Tag 00NP, permanent. Cite it as [Bourbaki, Tag 00NP].

Algebra, VIII, p. 403, § 21. Linear Representations of Finite Groups

Let H be a subgroup of G, and let (M,σ)(M, \sigma ) be a linear representation of H. The canonical homomorphism ι:\iota : IndHG(σ)→^G_H(\sigma )\rightarrow CoindHG(σ)^G_H(\sigma ) is injective. If the subgroup H has finite index in G, then ι\iota is an isomorphism of K[G]-modules.

Let S⊂GS\subset G be a system of representatives of G/HG/H. The family (s)s∈S(s)_{s\in S} is a basis of the right K[H]-module K[G]. It follows that the mapping M(S)→M^{(S)}\rightarrow IndHG(σ)^G_H(\sigma ) defined by (ms)s∈S↦∑s∈Ss⊗ms(m_s)_{s\in S}\mapsto \sum_{s\in S}s\otimes m_s is an isomorphism of K-modules. For all s,s′∈Ss, s'\in S and every m∈Mm\in M, we have the relations

ι(s′⊗m)(s−1)={mif s=s′,0otherwise. \iota (s'\otimes m)(s^{-1}) =\begin{cases} m & \text{if } s=s',\\ 0 & \text{otherwise.}\end{cases}

It follows that ι′\iota ' is injective.

Suppose that H has finite index in G. The set S is then finite; let ρ\rho be the mapping from CoindHG(σ)^G_H(\sigma ) to IndHG(σ)^G_H(\sigma ) given by u↦∑s∈Ss⊗u(s−1)u\mapsto \sum_{s\in S}s\otimes u(s^{-1}). It satisfies (ι∘ρ(u))(s−1)=u(s−1)(\iota \circ \rho (u))(s^{-1}) =u(s^{-1}) for u∈u\in CoindHG(σ)^G_H(\sigma ) and s∈Ss\in S. Since the family (s−1)s∈S(s^{-1})_{s\in S} is a basis of the left K[H]-module K[G], the mapping ι∘ρ\iota \circ \rho is the identity mapping. Consequently, ι\iota is bijective with inverse bijection ρ\rho.

Let H be a subgroup of G of finite index. Let uu be a central function on H; denote by u0u^0 the function on G that extends uu and that is zero at every point of G - H. Let S be a system of representatives of G/HG/H. For g∈Gg\in G, set

(4) IndHG(u)(g)=∑s∈Su0(s−1gs)^G_H(u)(g) =\sum_{s\in S}u^0(s^{-1}gs).

Note that for all x,g∈Gx, g\in G and every h∈Hh\in H, we have u0((xh)−1gxh)=u^0((xh)^{-1}gxh) = u0(x−1gx)u^0(x^{-1}gx). It follows that IndHG(u)^G_H(u) is a central function on G that does not depend on the choice of S. We thus define a K-linear mapping IndHG^G_H from ZK(H)\mathscr{Z}_K(H) to ZK(G)\mathscr{Z}_K(G).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.