Bourbaki

Exercise 15, § 21

Tag 00OO, permanent. Cite it as [Bourbaki, Tag 00OO].

Algebra, VIII, p. 428

Bourbaki marks this one as harder than the rest.

Suppose that all representations of G are monomial; let us prove that G is solvable. Reasoning by induction on the order of G, we may assume that every quotient group of G different from G is solvable.

a) If G contains two distinct minimal nontrivial normal subgroups H1H_1 and H2H_2, then it is solvable (consider the canonical homomorphism from G to G/H1×G/H2G/H_1\times G/H_2).

Assume from now on that G admits a unique minimal nontrivial normal subgroup H.

b) Prove that a representation of G is faithful if its restriction to H is nontrivial. c) Let π\pi be a faithful representation of minimal degree; there exist subgroups HiH_i of G and representations σi\sigma_i of HiH_i of degree 1 such that π\pi is isomorphic to ⨁\bigoplus IndHiG(σi)^G_{H_i}(\sigma_i). Let π0=⨁\pi_0=\bigoplus IndHiG(εHi)^G_{H_i}(\varepsilon_{H_i}), where εHi\varepsilon_{H_i} denotes the unit representation. Prove that the kernel of π0\pi_0 is commutative and nontrivial (observe that π0\pi_0 is irreducible); deduce that G is solvable.

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