Let n be a Lie subalgebra of gl(V) consisting of nilpotent endomorphisms, and N the subgroup expn of GL(V)(§3, no. 1, Lemma 1).
(i) Let ρ be a finite dimensional linear representation of n on W, such that the elements of ρ(n) are nilpotent, W′ a vector subspace of W stable under ρ,ρ1 and ρ2 the subrepresentation and quotient representation of ρ defined by W′,π,π1,π2 the representations of N compatible with ρ,ρ1,ρ2(§3, no. 1). Then π1,π2 are the subrepresentation and quotient representation of π defined by W′.
(ii) Let ρ1,ρ2 be finite dimensional linear representations of n such that the elements of ρ1(n) and ρ2(n) are nilpotent, and π1,π2 the representations of N compatible with ρ1,ρ2. Then π1⊗π2 is the representation of N compatible with ρ1⊗ρ2.
(iii) Let ρ1,ρ2 be finite dimensional linear representations of n on vector spaces V1,V2, such that the elements of ρ1(n) and ρ2(n) are nilpotent, ρ the representation of n on Hom(V1,V2) determined by ρ1,ρ2. Let π1,π2 be the representations of N compatible with ρ1,ρ2, and π the representation of N on Hom(V1,V2) determined by π1,π2. Then π is the representation of N compatible with ρ.
Assertion (i) is clear. Let ρ1,ρ2,π1,π2 be as in (ii). If x∈n, we have, since ρ1(x)⊗1 and 1⊗ρ2(x) commute,
exp(ρ1(x)⊗1+1⊗ρ2(x)) = exp(ρ1(x)⊗1). exp(1 ⊗ρ2(x))
= (exp ρ1(x))⊗1.1⊗ (expρ2(x))
= (exp ρ1(x))⊗ (expρ2(x))
=π1(exp x)⊗π2(exp x)
=(π1⊗π2)(exp x),
hence (ii). Let ρ1,ρ2,ρ,π1,π2,π,V1,V2 be as in (iii). If v1∈ EndV1 and v2∈ EndV2, denote by Rv1 and Lv2 the maps u→uv1 and u→v2u from Hom(V1,V2) to itself; these maps commute and ρ(x)u=(Lρ2(x)−Rρ1(x))u, so
expρ(x).u= exp Lρ2(x). exp R−ρ1(x).u
=Lexpρ2(x).Rexp(−ρ1(x)).u
=Lπ2(expx).Rπ1(exp(−x)).u
=π(exp x).u,
hence (iii).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.