Bourbaki

Proposition 4

Tag 00Y6, permanent. Cite it as [Bourbaki, Tag 00Y6].

Lie Groups and Lie Algebras, chapter VIII, § 1. The Lie algebra sl(2, k) and its representations

Let E be a finite dimensional sl(2,k)\mathfrak{s}\mathfrak{l}(2, k)-module, mm an integer ≥0\geq 0, PmP_m the set of primitive elements of weight mm. Let L be the vector space of homomorphisms from the sl(2,k)\mathfrak{s}\mathfrak{l}(2, k)-module V(m)V(m) to the sl(2,k)\mathfrak{s}\mathfrak{l}(2, k)-module E. The map f→f(um)f \rightarrow f(u^m) from L to E is linear, injective, and its image is Pm∪{0}P_m\cup \{0\}.

This map is clearly linear, and it is injective because umu^m generates the sl(2,k\mathfrak{s}\mathfrak{l}(2, k)-module V(m)V(m). If f∈Lf\in L,

X+(f(um))=f(X+um)=0,H(f(um))=f(Hum)=mf(um) X_+(f(u^m)) =f(X_+u^m) = 0,H(f(u^m)) =f(Hu^m) =mf(u^m)

so f(um)∈Pm∪{0}f(u^m)\in P_m\cup \{0\}. Let e∈Pme\in P_m, and V the submodule of E generated by ee. By Prop. 1, there exists an isomorphism from the module V(m)V(m) to the module V that takes umu^m to ee. Then L(um)=Pm∪{0}L(u^m) = P_m\cup \{0\}.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

Transcribed from the printed volume. Not translated.