Exercise 10, § 3
Tag 010O, permanent. Cite it as [Bourbaki, Tag 010O].
Lie Groups and Lie Algebras, VIII, 230
Bourbaki marks this one as harder than the rest.
Let be a semi-simple Lie algebra, and an element of . We say that is diagonalizable if ad is diagonalizable (Algebra, Chap. VII), in other words, if there exists a basis of consisting of eigenvectors of ad .
a) Let be a commutative subalgebra of consisting of diagonalizable elements, and let L be the set of weights of in the representation ad. The set L is a finite subset of containing 0 (unless ) and . Show that there exists a subset M of L such that L -- is the disjoint union of M and , and such that . If M has these properties, put , and . The algebra is the commutant of in ; it is reductive in (Chap. VII, §1, no. 5), and its Cartan subalgebras are the Cartan subalgebras of (Chap. VII, §2, no. 3). Show that is a
This exercise was communicated to us by A. JOSEPH. parabolic subalgebra of , and that is the set of nilpotent elements of the radical of . (Use the fact that is contained in a Cartan subalgebra of and reduce, by extension of scalars, to the case in which this subalgebra is splitting.)
b) Retain the hypotheses and notations of a), and assume in addition that is splittable. Show that is contained in a splitting Cartan subalgebra of . (Take a splitting Cartan subalgebra of contained in ; then there exists a unique Cartan subalgebra of such that is contained in ; show that is a splitting Cartan subalgebra of , and that contains )
Solution
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