Let (g,h,B,(Xα)α∈B) be a framed semi-simple Lie algebra. Let (n(α,β))α,β∈B and (Xα)α∈B∪(−B) be the corresponding Cartan matrix and generating family.
(i) The family ((Xα,Hα,X−α))α∈B and the relations (16) to (22) of no. 3 constitute a presentation of g.
(ii) The family (Xα)α∈B and the relations (21) of no. 3 constitute a presentation of the subalgebra of g generated by (Xα)α∈B.
Let R be the root system of (g,h). Applying to R and B the constructions of nos. 2 and 3, we obtain objects that we shall denote by a′,g′,Xα′,Hα′,... instead of a,g,Xα,Hα,....
There exists a homomorphism φ from the Lie algebra g′ to the Lie algebra g such that φ(Xα′)=Xα,φ(Hα′)=Hα,φ(X−α′)=X−α for all α∈B (Prop. 1). Since dim g′ = Card R + Card B = dimg,φ is bijective. This proves (i).
The subalgebra of g′=a′/(n′⊕θ′n′)=(a+′⊕a′0⊕a−′)/(n′⊕θ′n′) generated by (Xα′)α∈B can be identified with a+′/n′. In view of Prop. 3 and the definition of n′, this proves (ii).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.