Bourbaki

Exercise 18, § 7

Tag 014U, permanent. Cite it as [Bourbaki, Tag 014U].

Lie Groups and Lie Algebras, VIII, 243

Bourbaki marks this one as harder than the rest.

Choose a positive non-degenerate symmetric bilinear form (⋅∣⋅)(\cdot | \cdot ) on hR∗\mathfrak{h}^*_{\mathbf{R}} invariant under W. Let λ∈P++\lambda \in P_{++}.

a) Let μ\mu be a weight of E(λ)E(\lambda ). Write λ−μ\lambda -\mu in the form ∑α∈Bkαα\sum_{\alpha\in B}k_{\alpha}\alpha. Let α∈B\alpha \in B be

such that kα≠0k_{\alpha}\not= 0. Show that there exists α1,...,αn∈B\alpha_1, . . . , \alpha_n\in B such that (λ∣α1)≠0(\lambda |\alpha_1)\not= 0, (α1∣α2)≠0,...,(αn−1∣αn)≠0,(αn∣α)≠0(\alpha_1|\alpha_2)\not= 0, . . . ,(\alpha_{n-1}|\alpha_n)\not= 0,(\alpha_n|\alpha )\not= 0.

b) Let vv be a primitive element of E(λ)E(\lambda ), and let α1,...,αn∈B\alpha_1, . . . , \alpha_n\in B satisfy the following conditions:

(i) (αi∣αi+1)≠0(\alpha_i|\alpha_{i+1})\not= 0 for i=1,2,...,n−1i= 1,2, . . . , n-1;

(ii) (αi∣αj)=0(\alpha_i|\alpha_j) = 0 for j>i+1j > i+ 1;

(iii) λ(Hα1)≠0\lambda (H_{\alpha_1})\not= 0 and λ(Hα2)=⋯=λ(Hαn)=0\lambda (H_{\alpha_2}) =\cdots =\lambda (H_{\alpha_n}) = 0.

Show that X−αnX−αn−1...X−α1v≠0X_{-\alpha_n}X_{-\alpha_{n-1}}. . . X_{-\alpha_1}v\not= 0. (Observe that, for 1≤s≤n1\leq s\leq n,

λ−α1−⋯−αs−1+αn \lambda -\alpha_1- \cdots -\alpha_{s-1}+\alpha_n

is not a weight of E(λ)E(\lambda ), and deduce that XαsX−αsX−αs−1...X−α1v≠0X_{\alpha_s}X_{-\alpha_s}X_{-\alpha_{s-1}}. . . X_{-\alpha_1}v\not= 0 by induction on s.)s.) If σ∈Sn\sigma \in \mathfrak{S}_n and σ≠1\sigma \not= 1, then X−ασ(n)X−ασ(n−1)...X−ασ(1)v=0X_{-\alpha_{\sigma(n)}}X_{-\alpha_{\sigma(n-1)}}. . . X_{-\alpha_{\sigma(1)}}v= 0. (Let rr be the smallest integer such that σ(r)≠r\sigma (r)\not=r. Use aa) to show that λ−ασ(1)−...−ασ(r)\lambda -\alpha_{\sigma(1)}-. . .-\alpha_{\sigma(r)} is not a weight of E(λ).)E(\lambda ).)

c) Let λ′∈P++\lambda '\in P_{++}. A chain joining λ\lambda to λ′\lambda ' is a sequence (α1,...,αn)(\alpha_1, . . . , \alpha_n) of elements of B such that n≥1,(λ∣α1)≠0,(α1∣α2)≠0,...,(αn−1∣αn)≠0n\geq 1, (\lambda |\alpha_1)\not= 0,(\alpha_1|\alpha_2)\not= 0, . . . ,(\alpha_{n-1}|\alpha_n)\not= 0, (αn∣λ′)≠0(\alpha_n|\lambda ')\not= 0. Such a chain is called minimal if no strict subsequence of (α1,...,αn)(\alpha_1, . . . , \alpha_n) joins λ\lambda to λ′\lambda '. In that case, we have (αi∣αj)=0(\alpha_i|\alpha_j) = 0 if ∣i−j∣≥2|i-j| \geq 2, (λ∣αi)=0(\lambda |\alpha_i) = 0 if i≥2i\geq 2 and (λ′∣αi)=0(\lambda '|\alpha_i) = 0 if i≤n−1i\leq n-1.

d) Let (α1,...,αn)(\alpha_1, . . . , \alpha_n) be a minimal chain joining λ\lambda to λ′\lambda '. If v′v' is a primitive vector in E(λ′)E(\lambda '), put:

vs=X−αsX−αs−1...X−α1v(s=0,1,...,n) v_s=X_{-\alpha_s}X_{-\alpha_{s-1}}. . . X_{-\alpha_1}v(s= 0,1, . . . , n)
vs′=X−αs+1X−αs+2...X−αnv′(s=0,1,...,n) v'_s=X_{-\alpha_{s+1}}X_{-\alpha_{s+2}}. . . X_{-\alpha_n}v'(s= 0,1, . . . , n)

a0=(λ∣α1),an=(−1)n(λ′∣αn),as=(−1)s+1(αs∣αs+1),1≤s≤n−1a_0= (\lambda |\alpha_1), a_n= (-1)^n(\lambda '|\alpha_n), a_s= (-1)^{s+1}(\alpha_s|\alpha_{s+1}), 1\leq s\leq n-1. Show that

∑s=0nasvs⊗vs′ \sum_{s=0}^na_sv_s\otimes v'_s

is a primitive element of E(λ)⊗E(λ′)E(\lambda )\otimes E(\lambda ') of weight λ+λ′−α1−⋯−αn\lambda +\lambda '-\alpha_1- \cdots -\alpha_n, and that it is unique up to homothety.

(Use bb) and c) to show that every element of E(λ)⊗E(λ′)E(\lambda )\otimes E(\lambda ') of weight

λ+λ′−α1−⋯−αn \lambda +\lambda '-\alpha_1- \cdots -\alpha_n

is a linear combination of the vs⊗vs′v_s\otimes v'_s. Then write down the condition for such a linear combination to be a primitive vector.)

Deduce that E(λ)⊗E(λ′)E(\lambda )\otimes E(\lambda ') contains a unique g\mathfrak{g}-submodule isomorphic to

E(λ+λ′−α1−⋯−αn) E(\lambda +\lambda '-\alpha_1- \cdots -\alpha_n)

(When n=1n= 1 we recover Exerc. 17.)

e) Let ww be a primitive element of E(λ)⊗E(λ′)E(\lambda )\otimes E(\lambda '). Assume that the weight ν\nu of ww is distinct from λ+λ′\lambda +\lambda '. Show that there exists a chain (α1,...,αn)(\alpha_1, . . . , \alpha_n) joining λ\lambda to λ′\lambda ' such that

ν≤λ+λ′−α1−⋯−αn \nu \leq \lambda +\lambda '-\alpha_1- \cdots -\alpha_n

(Let C be the set of α∈B\alpha \in B such that the coordinate of index α\alpha of λ+λ′−ν\lambda +\lambda '-\nu is ≠0\not= 0. Let D (resp. D′D') be the set of α∈C\alpha \in C such that there exists γ1,...,γt∈C\gamma_1, . . . , \gamma_t\in C satisfying (λ∣γ1)≠0(\lambda |\gamma_1)\not= 0 (resp. (λ′∣γ1)≠0(\lambda '|\gamma_1)\not= 0),(γ1∣γ2)≠0,...,(γt−1∣γt)≠0, (\gamma_1|\gamma_2)\not= 0, . . . ,(\gamma_{t-1}|\gamma_t)\not= 0, (γt∣α)≠0(\gamma_t|\alpha )\not= 0. Let Y (resp. Y′Y') be the set of weights of E(λ)E(\lambda ) (resp. E(λ′)E(\lambda ')) of the form λ−∑α∈Ckαα\lambda -\sum_{\alpha\in C}k_{\alpha}\alpha (resp. λ′−∑α∈Ckαα\lambda '-\sum_{\alpha\in C}k_{\alpha}\alpha ), with kα∈Nk_{\alpha}\in \mathbf{N}. Show that ww belongs to ((∑μ∈YE(λ)μ)⊗((∑μ′∈Y′E(λ′)μ′)((\sum_{\mu\in Y}E(\lambda )^\mu)\otimes ((\sum_{\mu'\in Y'}E(\lambda ')^{\mu'}). Using a) and the fact that ν≠λ+λ′\nu \not=\lambda +\lambda ',

show that D∩D′≠∅.)D\cap D'\not=\emptyset .)

f) Show the equivalence of the following properties:

(i) E(λ)⊗E(λ′)E(\lambda )\otimes E(\lambda ') is isomorphic to E(λ+λ′)E(\lambda +\lambda ').

(ii) E(λ)⊗E(λ′)E(\lambda )\otimes E(\lambda ') is a simple module.

(iii) There is no chain joining λ\lambda to λ′\lambda '.

(iv) R is the direct sum of two root systems R1R_1 and R1′R'_1 such that λ∈P(R1)\lambda \in P(R_1) and λ′∈P(R1′)\lambda '\in P(R'_1).

(v) g\mathfrak{g} is the product of two ideals s\mathfrak{s} and s′\mathfrak{s}' such that s′.E(λ)=0\mathfrak{s}'.E(\lambda ) = 0 and s.E(λ′)=0\mathfrak{s}.E(\lambda ') = 0.

(Use dd) to prove the equivalence of (ii) and (iii).)15^{15}

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Cites

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