Bourbaki

Exercise 16, § 2

Tag 01KB, permanent. Cite it as [Bourbaki, Tag 01KB].

Lie Groups and Lie Algebras, VII, 57

Bourbaki marks this one as harder than the rest.

Let g\mathfrak{g} be a solvable complex Lie algebra, h\mathfrak{h} a Cartan subalgebra of g\mathfrak{g}, g=⨁gλ(h)\mathfrak{g}=\bigoplus\mathfrak{g}^{\lambda}(\mathfrak{h}) the corresponding decomposition of g\mathfrak{g} into primary subspaces, with g0(h)=h\mathfrak{g}^0(\mathfrak{h}) =\mathfrak{h}.

a) Show that the restrictions to h\mathfrak{h} of the linear forms called roots of g\mathfrak{g} in Chap. III, §9, Exerc. 17c)17c) are the weights of h\mathfrak{h} in g\mathfrak{g}, i.e. the λ\lambda such that gλ(h)≠0\mathfrak{g}^{\lambda}(\mathfrak{h})\not= 0; deduce that such a λ\lambda vanishes on h∩Dg\mathfrak{h}\cap \mathscr{D}\mathfrak{g}.

b) Let (x,y)→[x,y]′(x, y) \rightarrow [x, y]' be the alternating bilinear map from g×g\mathfrak{g}\times \mathfrak{g} to g\mathfrak{g} with the following properties:

(i) If x∈gλ(h),y∈gμ(h)x\in \mathfrak{g}^{\lambda}(\mathfrak{h}), y\in \mathfrak{g}^\mu(\mathfrak{h}), with λ≠0,μ≠0\lambda \not= 0, \mu\not= 0, then [x,y]′=[x,y][x, y]'= [x, y];

(ii) if x∈g0(h),y∈gμ(h)x\in \mathfrak{g}^0(\mathfrak{h}), y\in \mathfrak{g}^\mu(\mathfrak{h}), then [x,y]′=[x,y]−μ(x)y[x, y]'= [x, y]-\mu(x)y.

Show that this gives a new Lie algebra structure on g\mathfrak{g} (use aa))). Denote it by g′\mathfrak{g}'.

c) Show that, if x∈gλ(h)x\in \mathfrak{g}^{\lambda}(\mathfrak{h}), the map ad′x:y→[x,y]′'x:y \rightarrow [x, y]' is nilpotent. Deduce that g′\mathfrak{g}' is nilpotent (apply Exerc. 11 of Chap. I, §4 to the set E of ad′x'x, where xx belongs to the union of the gλ(h)\mathfrak{g}^{\lambda}(\mathfrak{h})).

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