Let (Bi)i∈I be a family of topological spaces and let, for each i∈I, (Xi,pi) and (Yi,qi) be Bi-spaces. Put B=∏i∈IBi, X=∏i∈IXi and Y=∏i∈IYi. Endowed with the continuous mapping p=∏ipi (resp. q=∏iqi), the topological space X (resp. Y) is a B-space. By the associativity isomorphism of the topological products of ∏i(Xi×Yi) onto (∏iXi)×(∏iYi)=X×Y (TG, I, p. 25, prop. 2), the subspace ∏i(Xi×BiYi) of ∏i(Xi×Yi) is identified with X×BY.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.